Splitting a python list with common end points

Question

Suppose I have a python list as: points_list = [1, 2, 3, 4, 5, 6, 7, 8, 9,1]

And I need to split this list containing the number of elements in the index_list=[2, 2, 6, 3] But having common endpoints

That is:

First 2 elements from points_list : [1,2]
Next 2 elements from the points_list but it should start from the place it stopped before : [2,3]
Then the next 6 elements : [3,4,5,6,7,8]
Finally, 3 elements in the same way : [8,9,1]

Ultimately, what I expect is to have something like: [[1,2],[2,3],[3,4,5,6,7,8],[8,9,1]] which corresponds to the number of elements mentioned in the index_list=[2, 2, 6, 3]

Can you please help me to perform this task

Asked By: Charith

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Source

Answer 1

Here’s my code:

points_list = [1, 2, 3, 4, 5, 6, 7, 8, 9,1]
index_list=[2, 2, 6, 3]
res = []
end_point = 0
for i in index_list:
    temp_list = points_list[end_point:end_point+i] # Get the list
    res.append(temp_list) # Append it
    end_point = points_list.index(temp_list[-1]) # Get the index of the last value
print(res)

Support for repeating numbers (thanks to azro and S.B):

points_list = [3, 2, 3, 4, 5, 6, 2, 8, 9, 1]
index_list=[2, 2, 6, 3]
res = []
for i in index_list:
    res.append(points_list[:i]) # Append it
    points_list = points_list[i-1:] # Reconfigure list
print(res)

Answered By: The Myth

Splitting a python list with common end points

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