Get dataframe cell value based on substring
Question:
I am trying to search for a substring across my dataframe (no specific column) and get in return the value of the cell.
For example:
Column A
Column B
Red apple
carrots
Blue Car
Banana
I’d like to search the cell which contains “Apple” and i should get in return “Red apple”.
i have been successful returning the row which contains the value as following:
df[df.apply(lambda row: row.astype(str).str.contains(“Apple”, case=false).any, axis=1)]
Or the column name which contains it:
df.apply(lambda x: x.str. contains(“Apple”, case=false).any())
But not exactly what i want, the full value of the cell which contains the substring.
Can I please get help?:)
Answers:
One option is to stack and use boolean indexing:
s = df.stack()
out = s[s.str.contains('apple')]
output:
0 Column A Red apple
dtype: object
If you expect a single match:
out = s[s.str.contains('apple')].squeeze()
output: 'Red apple'
I am trying to search for a substring across my dataframe (no specific column) and get in return the value of the cell.
For example:
| Column A | Column B |
|---|---|
| Red apple | carrots |
| Blue Car | Banana |
I’d like to search the cell which contains “Apple” and i should get in return “Red apple”.
i have been successful returning the row which contains the value as following:
df[df.apply(lambda row: row.astype(str).str.contains(“Apple”, case=false).any, axis=1)]
Or the column name which contains it:
df.apply(lambda x: x.str. contains(“Apple”, case=false).any())
But not exactly what i want, the full value of the cell which contains the substring.
Can I please get help?:)
One option is to stack and use boolean indexing:
s = df.stack()
out = s[s.str.contains('apple')]
output:
0 Column A Red apple
dtype: object
If you expect a single match:
out = s[s.str.contains('apple')].squeeze()
output: 'Red apple'