Repeatedly sample and combine elements of a list
Question:
Suppose we have a list L = ['a', 'b', 'c'], I would like to perform a group sampling of L to generate an expected result:
[['a'], ['b'], ['c'], ['a', 'b'], ['a', 'c'], ['b', 'c'], ['a', 'b', 'c']]
We can see, in this final output, a list of lists, its each element, there are no repeated elements without considering the order. How to implement it in Python?
Answers:
One way of doing it is using combinations from itertools module. Do it in a for loop and change its r= parameter every time. r=1, r=2, until r=len(L):
from itertools import combinations
lst = ["a", "b", "c"]
print([list(item) for i in range(1, len(lst) + 1) for item in combinations(lst, i)])
output:
[['a'], ['b'], ['c'], ['a', 'b'], ['a', 'c'], ['b', 'c'], ['a', 'b', 'c']]
Suppose we have a list L = ['a', 'b', 'c'], I would like to perform a group sampling of L to generate an expected result:
[['a'], ['b'], ['c'], ['a', 'b'], ['a', 'c'], ['b', 'c'], ['a', 'b', 'c']]
We can see, in this final output, a list of lists, its each element, there are no repeated elements without considering the order. How to implement it in Python?
One way of doing it is using combinations from itertools module. Do it in a for loop and change its r= parameter every time. r=1, r=2, until r=len(L):
from itertools import combinations
lst = ["a", "b", "c"]
print([list(item) for i in range(1, len(lst) + 1) for item in combinations(lst, i)])
output:
[['a'], ['b'], ['c'], ['a', 'b'], ['a', 'c'], ['b', 'c'], ['a', 'b', 'c']]