How to remove all punctuations from string except those in decimal numbers in Python?
Question:
Input is the code I’m using, Output is the output I’m getting, required output is the output I want.
Input:
import regex as re
keyword = 'Auto: tab suspender 2.0 pro'
keyword = re.sub(r'[^ws]','', keyword)
words = re.findall('w+', keyword)
print(keyword)
print(len(words))
words
Output:
Auto tab suspender 20 pro
5
['Auto', 'tab', 'suspender', '20', 'pro']
Required Output:
Auto tab suspender 2.0 pro
5
['Auto', 'tab', 'suspender', '2.0', 'pro']
Answers:
I would use re.findall here:
keyword = 'Auto: tab suspender 2.0 pro'
matches = re.findall(r'd+(?:.d+)?|w+', keyword)
print(matches) # ['Auto', 'tab', 'suspender', '2.0', 'pro']
The regex pattern used here first attempts to match an integer or float, and that failing will look for words:
d+ match an integer(?:.d+)? or maybe a float| ORw+ match a word
Input is the code I’m using, Output is the output I’m getting, required output is the output I want.
Input:
import regex as re
keyword = 'Auto: tab suspender 2.0 pro'
keyword = re.sub(r'[^ws]','', keyword)
words = re.findall('w+', keyword)
print(keyword)
print(len(words))
words
Output:
Auto tab suspender 20 pro
5
['Auto', 'tab', 'suspender', '20', 'pro']
Required Output:
Auto tab suspender 2.0 pro
5
['Auto', 'tab', 'suspender', '2.0', 'pro']
I would use re.findall here:
keyword = 'Auto: tab suspender 2.0 pro'
matches = re.findall(r'd+(?:.d+)?|w+', keyword)
print(matches) # ['Auto', 'tab', 'suspender', '2.0', 'pro']
The regex pattern used here first attempts to match an integer or float, and that failing will look for words:
d+match an integer(?:.d+)?or maybe a float|ORw+match a word