please help me with this python exercise

Question

input = [[0,1,2,3,4,5], [0,1,2,3,4,5], [0,1,2,3,4,5]]
output = [0****0, *1**1*, **22**]

This is what I’ve tried so far:

for x in input:
    for y in x:
        if int(x.index(y)) == int(input.index(x)):

And I got stuck. I don’t know how to make the value of the [0] index == that of the last index (and the [1] index == the [-2] index and so on) and then change the rest into ‘*’

Asked By: bestpythonprogrammer

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Source

Answer 1

inp = [[0,1,2,3,4,5], [0,1,2,3,4,5], [0,1,2,3,4,5]]
# out = [0****0, *1**1*, **22**] 

out = [] # here we create a list for finale output, now it's empty 

count = 0   #this variable count we use for knowing what is the index iterable element
for i in inp:       # ordinary for loop, we eterate inp. on first iteration i == inp[0], on sec i == inp[1], etc 
    s = list('*'*len(i))    #the same as as_digit(lengh of element i ) times '*'. like ['*','*','*','*','*','*',]
    s[count] = str(i[count])        #here we change list s by index count. it's to equal index count from i 
    s[-(count+1)] = str(i[count])   #the same action but from right side 
    out.append(''.join(s))          #''.join(s) makes list s into just string, out.append() append to out
    count+=1        #each eteration we +1 to count for knowing the index of i in inp during next iteration

print(out)      #['0****0', '*1**1*', '**22**']

Answered By: Dmitriy Neledva

please help me with this python exercise

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