How to get location of label in list in dataframe in pandas

Question

I want to get the uid using name
for eg: someFunctionToFindUidOfName(‘Akt’) //should return uid = 0, but don’t know how to get that i am new to dataFrames please explain the answer
I also want to checkif dataFrame has username and password if it has it will print "user found!"

please answer in 1 and 2 differently and please explain as much as u can in simple terms

Asked By: Ak47HG

||

Source

Answer 1

To get the uid from the name just simply use that:
```
 dataFrame[dataFrame['name'] == 'Akt']['uid']
```

Do you mean if name and password columns exist?

 if 'name' in dataFrame.keys() and 'password' in dataFrame.keys():
     print('user found')

Hope it helps

Answered By: Shay Levi

Answer 2

I think this is what you are looking for:

First to construct a DataFrame with the same format as yours:

import pandas as pd

d = {'name': ['name1', 'name2', 'name3'], 'password' : ['1234', '4567', abcd']}

df = pd.DataFrame.from_dict(d)
df.index.name = 'UID'
print(df)

which will give the output below. Notice that the first column is different – it is the index as in your data.

      name password
UID                
0    name1     1234
1    name2     4567
2    name3     abcd

Then code to get an uid and test it.

def get_uid(want_name):
    result = df[df['name'] == want_name]
    if result.empty:
        return('No such user from get_uid ' + want_name)
    else:
        return (want_name + ' uid is ' + str(result.index.item()))
              

print(get_uid('name2'))
print(get_uid('name4'))

How this works is that to select the row with the query name and if it exists get the index item (that is under the UID heading). As it is a number it is converted to a string. So it gives:

name2 uid is 1
No such user from get_uid name4

Next use a similar approach to check for a user and get the password:

def check_user(want_name):
    result = df[df['name'] == want_name]
    if(result.empty):
        return ('No such user from check_user ' + want_name)
    else:
        return (want_name +' User found with password ' + result['password'].item())
           

print(check_user('name2'))
print(check_user('name4'))

which gives results:

name2 User found with password 4567
No such user from check_user name4

The part that might need explaining is result = df[df['name'] == want_name]. What this does is select from the DataFrame that part where the expression inside df[ ] is True. Then the result can be used to give the part of the data of interest. To check both user and password then:

def check_user_pass(want_name, try_pass):
        result = df[df["name"] == want_name]
        if result.empty:
            return 'No such user'
        else:
            real_pass = result["password"].item()
            if real_pass != try_pass:
                return 'No such user *'
        return 'User found'
    
print(check_user_pass('name1', '1234'))

Answered By: user19077881

How to get location of label in list in dataframe in pandas

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