How to zip 2 lists but 1 list acts as a single unit?
Question:
I have
a = [5,3,7]
b = [9,4]
I want
c = [5,3,7,9,5,3,7,4]
Preferably a 1 liner solution that returns the desired output. List has to be flat.
I have tried the following:
[i if j==0 else j for i in [7,4] for j in [5,3,7,0]]
But am wondering if there is an even shorter/cleaner solution.
Answers:
I am not sure whether the following is cleaner, but here’s an option:
a = [5,3,7]
b = [9,4]
output = [x for y in b for x in [*a, y]]
print(output) # [5, 3, 7, 9, 5, 3, 7, 4]
At least it is better than the original code in that it allows for a to have 0 (or any value) as its element.
I have
a = [5,3,7]
b = [9,4]
I want
c = [5,3,7,9,5,3,7,4]
Preferably a 1 liner solution that returns the desired output. List has to be flat.
I have tried the following:
[i if j==0 else j for i in [7,4] for j in [5,3,7,0]]
But am wondering if there is an even shorter/cleaner solution.
I am not sure whether the following is cleaner, but here’s an option:
a = [5,3,7]
b = [9,4]
output = [x for y in b for x in [*a, y]]
print(output) # [5, 3, 7, 9, 5, 3, 7, 4]
At least it is better than the original code in that it allows for a to have 0 (or any value) as its element.