Regex python do lookahead in a conditional statement
Question:
I’m trying to do lookaheads in a conditional statement.
Explanation by words:
(specified string that has to be a number (decimal or not) or a word character, a named capturing group is created) (if the named capturing group is a word character then check if the next string is a number (decimal or not) with a lookahead else check if the next string is a word character with a lookahead)
To understand, here some examples that are matched or not:
a 6 or 6.4 b-> matched, since the first and the second string haven’t the same "type"
ab 7 or 7 rt -> not matched, need only a single word character
R 7.55t -> not matched, 7.55t is not a valid number
a r or 5 6-> not matched, the first and the second string have the same "type" (number and number, or, word character and word character)
I’ve already found the answer for the first string: (?P<var>([a-zA-Z]|(-?d+(.d+)?)))
I’ve found nothing on Internet about lookaheads in a condition statement in Python.
The problem is that Python doesn’t support conditional statement like PCRE:
Python supports conditionals using a numbered or named capturing group. Python does not support conditionals using lookaround, even though Python does support lookaround outside conditionals. Instead of a conditional like (?(?=regex)then|else), you can alternate two opposite lookarounds: (?=regex)then|(?!regex)else. (source: https://www.regular-expressions.info/conditional.html)
Maybe there’s a better solution that I’ve planned or maybe it’s just impossible to do what I want, I don’t know.
What I tried: (?P<var>([a-zA-Z]|(-?d+(.d+)?))) (?(?=[a-zA-Z])(?=(-?d+(.d+)?))|(?=[a-zA-Z]))(?P=var) but that doesn’t work.
Answers:
The named capture group (?P<var>...) contains the actual text which matched, not the regex itself. There is a way to create a named regex, too; but it’s probably not particularly necessary or useful here.
Simply spell out the alternatives:
((?<![a-zA-Z0-9])[a-zA-Z]s+-?d+(.d+)?(?![a-zA-Z.0-9])|(?<![a-zA-Z.0-9])-?d+(.d+)?s+[a-zA-Z](?![a-zA-Z0-9]))
If you genuinely require the second token to remain unmatched, it should be obvious how to change the parts starting at each s into a lookahead.
I’m trying to do lookaheads in a conditional statement.
Explanation by words:
(specified string that has to be a number (decimal or not) or a word character, a named capturing group is created) (if the named capturing group is a word character then check if the next string is a number (decimal or not) with a lookahead else check if the next string is a word character with a lookahead)
To understand, here some examples that are matched or not:
a 6 or 6.4 b-> matched, since the first and the second string haven’t the same "type"
ab 7 or 7 rt -> not matched, need only a single word character
R 7.55t -> not matched, 7.55t is not a valid number
a r or 5 6-> not matched, the first and the second string have the same "type" (number and number, or, word character and word character)
I’ve already found the answer for the first string: (?P<var>([a-zA-Z]|(-?d+(.d+)?)))
I’ve found nothing on Internet about lookaheads in a condition statement in Python.
The problem is that Python doesn’t support conditional statement like PCRE:
Python supports conditionals using a numbered or named capturing group. Python does not support conditionals using lookaround, even though Python does support lookaround outside conditionals. Instead of a conditional like (?(?=regex)then|else), you can alternate two opposite lookarounds: (?=regex)then|(?!regex)else. (source: https://www.regular-expressions.info/conditional.html)
Maybe there’s a better solution that I’ve planned or maybe it’s just impossible to do what I want, I don’t know.
What I tried: (?P<var>([a-zA-Z]|(-?d+(.d+)?))) (?(?=[a-zA-Z])(?=(-?d+(.d+)?))|(?=[a-zA-Z]))(?P=var) but that doesn’t work.
The named capture group (?P<var>...) contains the actual text which matched, not the regex itself. There is a way to create a named regex, too; but it’s probably not particularly necessary or useful here.
Simply spell out the alternatives:
((?<![a-zA-Z0-9])[a-zA-Z]s+-?d+(.d+)?(?![a-zA-Z.0-9])|(?<![a-zA-Z.0-9])-?d+(.d+)?s+[a-zA-Z](?![a-zA-Z0-9]))
If you genuinely require the second token to remain unmatched, it should be obvious how to change the parts starting at each s into a lookahead.