Python how to replace a None value in list with string None
Question:
I have list:
test_list = ['one','two',None]
Is there any simple way to replace None with ‘None’ ,without using index, because index for None maybe different each time.
I tried :
conv = lambda i : i or 'None'
res = [conv(i) for i in test_list]
It works ,is there another way to do so ?
Answers:
In this way all the data types would be converted to string
test_list = ['one','two',None]
res = [str(i) for i in test_list]
In this the data type will also be preserved
res = ['None' if i is None else i for i in test_list]
I have list:
test_list = ['one','two',None]
Is there any simple way to replace None with ‘None’ ,without using index, because index for None maybe different each time.
I tried :
conv = lambda i : i or 'None'
res = [conv(i) for i in test_list]
It works ,is there another way to do so ?
In this way all the data types would be converted to string
test_list = ['one','two',None]
res = [str(i) for i in test_list]
In this the data type will also be preserved
res = ['None' if i is None else i for i in test_list]