Is it the best way to create an array from a list of objects?
Question:
I have a list of objects stored in socialmedias variable. One parameter of SocialMedia class is called username. I want to create an array with all usernames from that list of objects socialmedias and I want to be sure I use the best way.
socialmedias = [obj1, obj2, obj3, ..., objN]
usernames = []
for sm in socialmedias:
usernames.append(sm.username)
print(usernames)
>> [username1, username2, username3, ..., usernameN]
Is there any other way to do it in less line of codes I used above?
Answers:
yes there is, you can use list comprehension like:
usernames = [sm.username for sm in socialmedias]
You could do
usernames = [sm.username for sm in socialmedias]
From: Extract list of attributes from list of objects in python
By memory I would say by using list comprehension:
socialmedias = [obj1, obj2, obj3, ..., objN]
usernames = [sm.username for sm in socialmedias]
print(usernames)
It should do the work.
Using a function.
list(map(lambda sm: sm.username, socialmedias))
I have a list of objects stored in socialmedias variable. One parameter of SocialMedia class is called username. I want to create an array with all usernames from that list of objects socialmedias and I want to be sure I use the best way.
socialmedias = [obj1, obj2, obj3, ..., objN]
usernames = []
for sm in socialmedias:
usernames.append(sm.username)
print(usernames)
>> [username1, username2, username3, ..., usernameN]
Is there any other way to do it in less line of codes I used above?
yes there is, you can use list comprehension like:
usernames = [sm.username for sm in socialmedias]
You could do
usernames = [sm.username for sm in socialmedias]
From: Extract list of attributes from list of objects in python
By memory I would say by using list comprehension:
socialmedias = [obj1, obj2, obj3, ..., objN]
usernames = [sm.username for sm in socialmedias]
print(usernames)
It should do the work.
Using a function.
list(map(lambda sm: sm.username, socialmedias))