Expanding an alphanumeric range given a list

Question

I have a list of alphanumeric items:

values=['1111X0-1111X3', 'A111X0-A111X3',...., ]

I would like to expand the last digit of every item in this list such that:

values_output = ['111X0', '111X1', '111X2', '111X3', 'A111X0', 'A111X1', 'A111X2', 'A111X3',...' ',...]

I found this answer on a similar post that uses regex:

import re

lst = ['4276-4279', 'I69-I71', 'V104-V112', '11528']
new = []
for l in lst:
    m = re.match(r'^([A-Z]*)(d+)-1(d+)$', l)
    if m:
        new += [m.group(1) + str(i) for i in range(int(m.group(2)), int(m.group(3))+1)]
    else:
        new += [l]

print(new)

However I could not figure out a pattern to match the items on my list.

Any input is greatly appreciated!

Asked By: ReynoldL

||

Source

Answer 1

You can use

re.search(r'^(w+?)(d+)-1(d+)$', l)

See the Python demo.

Details:

^ – start of string
(w+?) – Group 1: any one or more word chars as few as possible
(d+) – Group 2: one or more digits
- – a hyphen
1 – Group 1 value
(d+) – Group 3: one or more digits
$ – end of string.

Answered By: Wiktor Stribiżew

Expanding an alphanumeric range given a list

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