group by line break and execute regex
Question:
From one connector, I receive a very specific string format:
{#{123}#};{#{abc}#}n{#{345}#};{#{def}#}n{#{789}#};{#{ghi}#}
I can’t change that format. Currently, I use the regex (?s){#{(.*?)}#}. This results in a list ["123", "abc", "345", "def", "789", "ghi"]
Is it possible to get the output grouped by line? Something like [("123", "abc"), ("345", "def"), ("789", "ghi")] – I know i can also just use split in python. Is there any regex way? I tried a bit with www.regex101.com, however couldnt find a solution.
Answers:
Since you have pairs of matches on each line, you can capture them:
re.findall(r'{#{(.*?)}#};{#{(.*?)}#}', text)
See the Python demo.
Output:
[('123', 'abc'), ('345', 'def'), ('789', 'ghi')]
Note you should not use (?s) DOTALL inline flag since it makes . match across lines.
From one connector, I receive a very specific string format:
{#{123}#};{#{abc}#}n{#{345}#};{#{def}#}n{#{789}#};{#{ghi}#}
I can’t change that format. Currently, I use the regex (?s){#{(.*?)}#}. This results in a list ["123", "abc", "345", "def", "789", "ghi"]
Is it possible to get the output grouped by line? Something like [("123", "abc"), ("345", "def"), ("789", "ghi")] – I know i can also just use split in python. Is there any regex way? I tried a bit with www.regex101.com, however couldnt find a solution.
Since you have pairs of matches on each line, you can capture them:
re.findall(r'{#{(.*?)}#};{#{(.*?)}#}', text)
See the Python demo.
Output:
[('123', 'abc'), ('345', 'def'), ('789', 'ghi')]
Note you should not use (?s) DOTALL inline flag since it makes . match across lines.