How can I control three different threads using threading in Python?

Question

I have thread1, thread2 and thread3, global variable x and three different functions to increment x,

import threading
import time

#check = threading.Condition()
x=1

def add_by1():
    global x
    x+=1
    time.sleep(1)
    print(x)
    

def add_by2():
    x+=2
    time.sleep(1)
    print(x)

def add_by3():
    x+=3
    time.sleep(1)
    print(x)

if __name__==__main__:
    threading.Thread(target=add_by1).start()
    threading.Thread(target=add_by2).start()
    threading.Thread(target=add_by3).start()

# I want the output should print.. 
"""
2
4
7
8
10
13
14
16
19
and so on ..
"""

can I use the Condition(), if so how? can I use other threading classes?, how would I insert some codes on these functions?

Asked By: fardV

||

Source

Answer 1

I guess this approach is reliable. You can synchronize your threads using three lock objects – one for each.

The way this setup works is each thread acquires its lock and after doing its job, it releases next thread’s lock! IOW, add_by1 releases thread_lock_two, add_by2 releases thread_lock_three and lastly add_by3 releases thread_lock_one.

Initially you need to acquire thread_lock_two and thread_lock_three‘s lock so that only the first thread does its job.

Whenever the condition is met (you said x == 20), each thread should again release next thread’s lock also return !

import threading
from time import sleep

x = 1

thread_lock_one = threading.Lock()
thread_lock_two = threading.Lock()
thread_lock_three = threading.Lock()

thread_lock_two.acquire()
thread_lock_three.acquire()


def add_by1():
    global x
    while True:
        thread_lock_one.acquire()
        if x >= 20:
            thread_lock_two.release()
            return
        x += 1
        print(x)
        sleep(0.6)
        thread_lock_two.release()


def add_by2():
    global x
    while True:
        thread_lock_two.acquire()
        if x >= 20:
            thread_lock_three.release()
            return
        x += 2
        print(x)
        sleep(0.6)
        thread_lock_three.release()


def add_by3():
    global x
    while True:
        thread_lock_three.acquire()
        if x >= 20:
            thread_lock_one.release()
            return
        x += 3
        print(x)
        sleep(0.6)
        thread_lock_one.release()


if __name__ == "__main__":
    threading.Thread(target=add_by1).start()
    threading.Thread(target=add_by2).start()
    threading.Thread(target=add_by3).start()

output:

Answered By: S.B

How can I control three different threads using threading in Python?

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