finding sum of fractions n/1 to 1/n

Question

I am trying to find the sum n/1 + (n-1)/2 + (n-2)/3 ... + 1/n. I am not getting the correct output

This is what I have

n = int(input("Please enter a positive integer: "))

sum2 = 0.0

for i in range(1, n-1):
    sum2 = sum2 + (i/1)

print("For n =", n, "the sum n/1 + (n-1)/2 + ... 1/n is", sum2)

My expected output for sum2 is 11.15 when 6 is entered as n but it’s not correct. What am I doing wrong?

Asked By: bee

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Source

Answer 1

When talking about the 2nd summation, besides the numerator decreasing one by one, the denominator also needs to increase one by one.

n = int(input("Please enter a positive integer: "))


sum2 = 0

for i in range(0, n):
    sum2 = sum2 + (n-i)/(i+1)

print("For n =", n, "the sum n/1 + (n-1)/2 + ... 1/n is", sum2)

Answered By: tanjavaner

finding sum of fractions n/1 to 1/n

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