How to add rows to a dataframe when values are recursively dependent?

Question

I have a data frame with columns a and b

df = pd.DataFrame(data = [[3, 6], [5, 10], [9, 18], [17, 34]], columns = ["a", "b"])

The structure of this data is as follows,

if a_t denotes the value of column a at row t and the same for b_t, then

b_t = 2 * a_t
a_t = b_{t – 1} – 1

See how the values of a are determined by the previous values of b and the values of b is determined by a. This recursive dependency means that I can’t simply use the .shift() command

We are given the value of a at row 0. How do I approach generating this data frame for a specified n rows efficiently, preferably without loops?

I attempted using loops. They’re inefficient once the calculations get more complicated and as n increases. Are there better ways to generate recursively related columns?

Asked By: Gerry Ongko

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Source

Answer 1

Here is my take on your interesting question, for instance with 3 as the value of a at row 0 and 10 as n:

import pandas as pd

A = 3
N = 10

dfs = [pd.DataFrame(data=[[A, 2 * A]], columns=["a", "b"])]
for _ in range(N - 1):
    dfs = dfs + [
        (dfs[-1].shift(-1, axis=1) - 1).pipe(
            lambda df_: df_.fillna(df_["a"].values[0] * 2)
        )
    ]

df = pd.concat(dfs, ignore_index=True)

Then:

print(df)
# Output
        a       b
0     3.0     6.0
1     5.0    10.0
2     9.0    18.0
3    17.0    34.0
4    33.0    66.0
5    65.0   130.0
6   129.0   258.0
7   257.0   514.0
8   513.0  1026.0
9  1025.0  2050.0

Answered By: Laurent

How to add rows to a dataframe when values are recursively dependent?

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