regex to get value and it's proper unit

Question

i use the following regex to extract values that appear before certain units:

([.d]+)s*(?:kg|gr|g)

What i want, is to include the unit of that specific value
for example from this string :

"some text 5kg another text 3 g more text 11.5gr end"

i should be getting :

["5kg", "3 g", "11.5gr"]

can’t wrap my head on how to modify the above expression to get the wanted result.
Thank you.

Asked By: oussama

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Answer 1

import re

p = re.compile('(?<!d|.)d+(?:.d+)?s*?(?:gr|kg|g)(?!w)')
print(p.findall("some text 5kg another text 3 g more text 11.5gr end"))

Answered By: Ricardo

Answer 2

Other solution (regex demo):

(?i)bd+.?d*s*(?:kg|gr?)b

(?i) – case insensitive
b – word boundary
- d+.?d* – match the amount
- s* – any number of spaces
- (?:kg|gr?) – match kg, g or gr
b – word boundary

import re

p = re.compile(r"(?i)bd+.?d*s*(?:kg|gr?)b")
print(p.findall("some text 5kg another text 3 g more text 11.5gr end"))

Prints:

['5kg', '3 g', '11.5gr']

Question: