Counting entries of a list

Question

I have a list:

final_list =['Angle1 &110.2 \\', 'Angle1 &110.2 \\', 'Angle3 (2) \\', 'Angle4 & 93 (2) \\']

for entry in final_list:
    print(entry)

For Latex formatting I need to connect these entries (over 100 entries total).
The list should look like this:

OUTPUT = 
Angle1 &110.2 &
Angle2 &110.2 \\
Angle3 (2) &
Angle4 & 93 (2) \\

I’ve tried to count the occurrences of "\\" in the entry

counter_slash = 0
for entry in final_list:
    counter_slash = final_list.count(entry)
    if counter_slash == 1:
        counter_slash += 1
        entry = entry.replace("\\", "&")
        print(entry)
    elif counter_slash == 2:
        counter_slash = 0
        print(entry)

However my output looks like this:

OUTPUT = 
Angle1 &110.2 &
Angle1 &110.2 &
Angle3 (2) &
Angle4 & 93 (2) &

Asked By: Tobbbe

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Source

Answer 1

What about this?


final_list =[   'Angle1 &110.2 \\', 
                'Angle1 &110.2 \\', 
                'Angle3 (2) \\', 
                'Angle4 & 93 (2) \\']
for i, entry in enumerate(final_list):
    final_list[i] = entry.replace(" \\", "")
print(f'{final_list[0]} & {final_list[1]} \\ {final_list[2]} & {final_list[3]} \\')

Answered By: aclayden

Answer 2

So what you’re doing with counter_slash = final_list.count(entry) is count how often entry is found in final_list. Which, if they’re all different, is going to be 1 for every list item.

It looks like you want to replace the \ in every other item with &, in which case you could do the following:

for i, entry in enumerate(final_list):
    if i % 2 == 0:
        print(entry.replace('\\', '&'))
    else:
        print(entry)

Answered By: Jasmijn

Counting entries of a list

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