# Counting entries of a list

## Question:

I have a list:

``````final_list =['Angle1 &110.2 \\', 'Angle1 &110.2 \\', 'Angle3 (2) \\', 'Angle4 & 93 (2) \\']

for entry in final_list:
print(entry)
``````

For Latex formatting I need to connect these entries (over 100 entries total).
The list should look like this:

``````OUTPUT =
Angle1 &110.2 &
Angle2 &110.2 \\
Angle3 (2) &
Angle4 & 93 (2) \\
``````

I’ve tried to count the occurrences of `"\\"` in the entry

``````counter_slash = 0
for entry in final_list:
counter_slash = final_list.count(entry)
if counter_slash == 1:
counter_slash += 1
entry = entry.replace("\\", "&")
print(entry)
elif counter_slash == 2:
counter_slash = 0
print(entry)
``````

However my output looks like this:

``````OUTPUT =
Angle1 &110.2 &
Angle1 &110.2 &
Angle3 (2) &
Angle4 & 93 (2) &
``````

``````
final_list =[   'Angle1 &110.2 \\',
'Angle1 &110.2 \\',
'Angle3 (2) \\',
'Angle4 & 93 (2) \\']
for i, entry in enumerate(final_list):
final_list[i] = entry.replace(" \\", "")
print(f'{final_list[0]} & {final_list[1]} \\ {final_list[2]} & {final_list[3]} \\')

``````

So what you’re doing with `counter_slash = final_list.count(entry)` is count how often `entry` is found in `final_list`. Which, if they’re all different, is going to be 1 for every list item.

It looks like you want to replace the `\` in every other item with `&`, in which case you could do the following:

``````for i, entry in enumerate(final_list):
if i % 2 == 0:
print(entry.replace('\\', '&'))
else:
print(entry)
``````
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