How to access package level variable

Question

Suppose i have package named src

    src
        - __init__.py
        - app.py

__init__.py

    ___version__ = '0.1.0'

    import os

    ENTRY_DIR = os.path.dirname(__file__)
    BASE_DIR = os path.dirname(ENTRY_DIR)

    DATA_DIR = os.path.join(BASE_DIR, 'data')

how can i access the variable DATA_DIR in app.py

I tried like this,

app.py

     from src import DATA_DIR

     print(DATA_DIR)

It didn’t worked, i got an error.

ModuleNotFoundError: No module named ‘src’

How can i acces the variable inside the app module

Asked By: ABHIJITH EA

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Source

Answer 1

it seems like you are referencing wrong path for that variable.

import the file in app.py

then you will be able to use variables from that file in same package.

use underscore with file name

import init

print(DATA_DIR)

Answered By: Marri

Answer 2

The __init__.py file is used to define how your package looks for an other one so you cannot do what you are trying to do since you are inside.

You can create a cfg.py like this :

# cfg.py

import os

ENTRY_DIR = os.path.dirname(__file__)
BASE_DIR = os path.dirname(ENTRY_DIR)
DATA_DIR = os.path.join(BASE_DIR, 'data')

So you can import DATA_DIR easily from app.py :

# app.py

from cfg import DATA_DIR

print(DATA_DIR)

If you need to use the variables defined in cfg.py outside of your package you can modified the __init__.py :

# __init__.py

___version__ = "0.1.0"

from .cfg import *

Answered By: Raida

How to access package level variable

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