How do I get my code to recall upon the function again to start over? (Python)

Question

Here is my code that I am working on. It is supposed to take a number from the user and if its a perfect number it says so, but if its not it asks to enter a new number. When I get to the enter a new number part, it doesn’t register my input. Can someone help me out?

def isPerfect(num):
    if num <= 0:                  
        return False
    total = 0                      
    for i in range(1,num):
        if num%i== 0:
            total = total + i
    if total == num:
        return True
    else:
        return False


def main():
    num = int(input("Enter a perfect integer: "))
    if isPerfect(num) == False:
        op = int(input(f"{num} is not a perfect number. Re-enter:"))
        isPerfect(op)
    elif isPerfect(num) == True:
        print("Congratulations!",num, 'is a perfect number.')

if __name__ == '__main__':
   main()

Asked By: Ryan

||

Source

Answer 1

you could just put a while True loop into your main function like so:

def main():
    first_run = True
    perfect_num_received = False
    while not perfect_num_received:
        if first_run:
            num = int(input("Enter a perfect integer: "))
            first_run = False
        if isPerfect(num) == False:
            num = int(input(f"{num} is not a perfect number. Re-enter:"))
        elif isPerfect(num) == True:
            perfect_num_received = True
            print("Congratulations!",num, 'is a perfect number.')

but also there is already a built in function to check for the data type of a variable so you could just do something like this maybe:

if type(num) == int:
    ...

Answered By: maxxel_

Answer 2

From the problem description, I assume that the program should terminate after the perfect number is found. There are two things which can be added, a loop to go over the input prompt each time the user feeds a number and a break condition after finding the perfect number. Here’s one implementation which works.

def main():
while True:
    num = int(input("Enter a perfect integer: "))
    if isPerfect(num) == False:
        num = int(input(f"{num} is not a perfect number. Re-enter: "))
        isPerfect(num)
    elif isPerfect(num) == True:
        print("Congratulations! ",num, ' is a perfect number.')
        break

Answered By: mrboran

How do I get my code to recall upon the function again to start over? (Python)

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