Change value of dictionary if it is in another dictionary

Question

I have two lists of generated dictionaries. One is like a template structured like:

list_of_dicts_template = [{'year': 0, 'week': 38, 'count_tickets': 0}, {'year': 0, 'week': 39, 'count_tickets': 0}]...

And another is a dictionary with values that we know:
known_values_list = [{'year': 2022, 'week': 39, 'tickets': 47}, {'year': 2022, 'week': 40, 'tickets': 3}]...
My problem is, I want to mix them in one list of dictionaries. Where if value of key ‘week’ is in list of dicts known_values_list, it will replace whole dict in list_of_dicts_template.

So the expected list of dicts would look like:
final_list = [{'year': 0, 'week': 38, 'count_tickets': 0}, {'year': 2022, 'week': 39, 'count_tickets': 47}, {'year': 2022, 'week': 40, 'tickets': 3}]...
`

I actually don’t know how to approach this problem. If I had only dicts without array, I would do something like:

for sub in dicts_template:
    if(sub in known_values):
        dicts_template[sub] = known_values[sub]

But if it’s in arrays, I’m completely lost.

Asked By: Jaroslav H.

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Source

Answer 1

You could use the following code:

for i,d1 in enumerate(list_of_dicts_template):
    for j, known_value_d in enumerate(known_values_list):
        if known_value_d['week'] == d1['week']:
            list_of_dicts_template[i] = known_value_d
            del known_values_list[j]

To add only delete the element in the known_values_list, if there shouldn’t be any duplicate weeks in the list_of_dicts_template.

Answered By: CodeKorn

Change value of dictionary if it is in another dictionary

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