# How to sort MultiIndex using values from a given column

## Question:

I have a DataFrame with 2-level index and column with the numerical values. I want to sort it by `level-0`

and `level-1`

index in such a way that the the order of 0-level index is determined by the sum of values from `Value`

column (descending), and the order of 1-level index is also determined by the values in `Value`

column. This is my code:

```
import pandas as pd
df = pd.DataFrame()
df["Index1"] = ["A", "A", "B", "B", "C", "C"]
df["Index2"] = ["X", "Y", "X", "Y", "X", "Y"]
df["Value"] = [1, 4, 7, 3, 2, 7]
df = df.set_index(["Index1", "Index2"])
df
```

And this is the desired output (B is at the top because the sum is 10 and then we have X first because 7 >3):

## Answers:

You can do this with ** pandas.DataFrame.sort_values** :

```
out= (
df
.assign(temp_col = df.groupby(level=0).transform("sum"))
.sort_values(by=["temp_col", "Value"], ascending=[False, False])
.drop(columns="temp_col")
)
```

#### # Output :

```
print(out)
Value
Index1 Index2
B X 7
Y 3
C Y 7
X 2
A Y 4
X 1
```