Different result when i switch positions of my two different functions

Note – I am using VSCode

Sample 1: In this example my function nextSquare() is been executed, but aFunc() is not been executed, as in, i get no output for my 2nd function

def nextSquare():
    i = 1
    while True:
        yield i*i
        i += 1
for num in nextSquare():
    if num<100:
        print(num)

def aFunc():
    print("This is inside our function")
print("This is outside of our funcion as a seperate entity")

aFunc()

Output:

Code/RoughWork.py
1
4
9
16
25
36
49
64
81

Sample 2: In this example my function nextSquare() is been executed, but aFunc() gives me output, all i did is, just shift aFunc() before nextSquare()

def aFunc():
    print("This is inside our function")
print("This is outside of our funcion as a seperate entity")

aFunc()

def nextSquare():
    i = 1
    while True:
        yield i*i
        i += 1
for num in nextSquare():
    if num<100:
        print(num)

Output:

Code/RoughWork.py
This is outside of our funcion as a seperate entity
This is inside our function
1
4
9
16
25
36
49
64
81

so when i used the sample 1: in the above code block, i expected that both the functions will get executed, but they didn’t, instead by rearranging the function’s positions, i got an output, so why is that why did the position of what existed before what mattered in this scenario,and when i try the same in jupyter notebook, the cell doesn’t run at all for sample 2.