Is there any way to make dictionary key,value pairs to tuple?

Question

I need to convert this dictionary:
{'A': 0, 'B': 1290, 'C': 515, 'D': 600}

Into this test case:
(A : 0) - (B : 1290) - (C : 515) - (D : 600)

This is how I derive my dictionary

    def stock_list(list_of_art, list_of_cat):
        new_dictionary = {}
        numbers = []
        for character in list_of_cat:
            if character not in new_dictionary:
                new_dictionary[character] = 0
        for word in list_of_art:
            first_element = word[0][0]
            for number in word:
                if number.isdigit():
                    numbers.append(number)
            make_str = "".join(numbers)
            numbers = []
            if first_element in new_dictionary:
                new_dictionary[first_element] += int(make_str)
        return new_dictionary

This is a sample call

stock_list(["BBAR 150", "CDXE 515", "BKWR 250", "BTSQ 890", "DRTY 600"],["A","B","C","D"])

Asked By: Joelinton

||

Source

Answer 1

Just iterate over the keys and values of your dictionary, and format them into a string.

d  = {'A': 0, 'B': 1290, 'C': 515, 'D': 600}

print(" - ".join(f'({k} : {v})' for k,v in d.items()))

#(A : 0) - (B : 1290) - (C : 515) - (D : 600)

Answered By: OneMadGypsy

Is there any way to make dictionary key,value pairs to tuple?

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