Trying to reorganize a random string so that all the letters are grouped up in the order that a different random string dictates

Question

I am creating a matrix that will list these a random string of letters that are used for colors and they are to be organized so that, for example all of the G’s will be together and then R, etc.

legoString = "YRRBRBYBGRBRGRRRYRGBRBGBBRBG"
shuffledColString = "YRBG"

for letter in shuffledColString:
    for index in range(len(legoString)):

        if letter == legoString[index]:
                legoString = legoString.replace(legoString[index], "") + "R"

        elif letter == legoString[index]:
                legoString = legoString.replace(legoString[index], "") + "G"

        elif letter == legoString[index]:
                legoString = legoString.replace(legoString[index], "") + "B"

        elif letter == legoString[index]:
                legoString = legoString.replace(legoString[index], "") + "C"

        elif letter == legoString[index]:
                legoString = legoString.replace(legoString[index], "") + "Y"

Asked By: KludgyCartoon79

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Source

Answer 1

try this

legoString = "YRRBRBYBGRBRGRRRYRGBRBGBBRBG"
shuffledColString = "YRBG"

ns="".join(sorted(legoString,key=lambda x:shuffledColString.index(x)))
print(ns)

#OR IF ABOVE IS NOT CLEAR
ns=""
for c in shuffledColString:
    ns=ns+ c*legoString.count(c)

print(ns)

Answered By: wrbp

Trying to reorganize a random string so that all the letters are grouped up in the order that a different random string dictates

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