trying to reverse words while maintaining order and print but having trouble figuring out the problem

Question

I have written code that should do as the title says but im getting "TypeError: can only join an iterable"
on line 12, in reverse_words d.append(”.join(c))

here is my following code-

def reverse_words(text):
    #makes 'apple TEST' into ['apple', 'TEST']
    a = text.split(' ')
    d = []
    for i in a:
        #takes 'apple' and turns it into ['a','p','p','l','e']
        b = i.split()
        #takes ['a','p','p','l','e'] and turns it into ['e','l','p','p','a']
        c = b.reverse()
        #takes ['e','l','p','p','a'] and turns it into 'elppa'
        #appends 'elppa' onto d
        d.append(''.join(c))
        #whole thing repeats for 'TEST' as well
    #joins d together by a space and should print out 'elppa TSET'
    print(' '.join(d))

reverse_words('apple TEST')

I know it has to do something that I messed up with c but I cannot identify it.

trying to reverse words while maintaining order but i got a type error

Asked By: yel fog

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Source

Answer 1

d.append('').join(d)

If this is what you intended try this, otherwise you’re gonna need to call a new variable and call .join() on that

Answered By: Atticus Reeves

Answer 2

Perhaps you could consider utilizing str.join on a comprehension that uses list slicing to reverse a string:

def reverse_words(text: str) -> str:
  return ' '.join(word[::-1] for word in text.split(' '))

Answered By: Sash Sinha

Answer 3

The reverse() method for lists reverses elements in-place and doesn’t return an iterable, meaning it will return a none object if the method runs successfully. You can modify your code like this:

def reverse_words(text):
    #makes 'apple TEST' into ['apple', 'TEST']
    a = text.split(' ')
    d = []
    for i in a:
        #takes 'apple' and turns it into ['a','p','p','l','e']
        b = i.split()
        #takes ['a','p','p','l','e'] and turns it into ['e','l','p','p','a']
        b.reverse()
        #takes ['e','l','p','p','a'] and turns it into 'elppa'
        #appends 'elppa' onto d
        d.append(''.join(b))
        #whole thing repeats for 'TEST' as well
    #joins d together by a space and should print out 'elppa TSET'
    print(' '.join(d))

reverse_words('apple TEST')

You can also use the reversed() method if you want the reversed list in a new variable like so:

def reverse_words(text):
    #makes 'apple TEST' into ['apple', 'TEST']
    a = text.split(' ')
    d = []
    for i in a:
        #takes 'apple' and turns it into ['a','p','p','l','e']
        b = i.split()
        #takes ['a','p','p','l','e'] and turns it into ['e','l','p','p','a']
        c = reversed(b)
        #takes ['e','l','p','p','a'] and turns it into 'elppa'
        #appends 'elppa' onto d
        d.append(''.join(c))
        #whole thing repeats for 'TEST' as well
    #joins d together by a space and should print out 'elppa TSET'
    print(' '.join(d))

reverse_words('apple TEST')

Answered By: parkdj1

trying to reverse words while maintaining order and print but having trouble figuring out the problem

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