Transforming a matrix by placing its elements in the reverse order of the initial in python

Question

im looking to solve the problem mentioned in the title without any specific functions that may or may not exist for this[ Example ]. Something along the lines of using mostly loops.

I tought about reversing each individual row using list.reverse() and then moving the rows around but im not sure how to implement it.

Asked By: Gui Pinto

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Source

Answer 1

Try This

Matrix = [[1,2,3],[4,5,6],[7,8,9]]
newMatrix = []
for line in range(len(Matrix)):
    Matrix[line].reverse()
    newMatrix.append(Matrix[line])

newMatrix.reverse()
print(newMatrix)

output

[[9, 8, 7], [6, 5, 4], [3, 2, 1]]

Answered By: Exile

Answer 2

try this new realization and this will not change the original Matrix

Matrix = [[1,2,3],[4,5,6],[7,8,9]]
newMatrix = []
for line in range(len(Matrix)):
    newMatrix.append(sorted(Matrix[line],reverse=True))

newMatrix.reverse()
print(newMatrix)
print(Matrix)

output:

[[9, 8, 7], [6, 5, 4], [3, 2, 1]]
[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

Answered By: Exile

Transforming a matrix by placing its elements in the reverse order of the initial in python

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