How to use all() in python?

Question

I want to check if all elements of a list are not present in a string.

ex :

    l = ["abc","ghi"]
    s1 = "xyzjkl"
    s2 = "abcdef"

So , when l is compared with s1 it should return True,
when l is compared with s2 it should return False.

This is what i tried :

    all(x for x in l if x not in s1) = True
    all(x for x in l if x not in s2) = True

I am getting True for both cases, But it should be false in second case.
Can someone please help, any solution will help, i just want to have it in a single line.

Thanks,

Asked By: Zzz

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Source

Answer 1

If the goal is:

Check that all elements of a list are not present in a string.

The pattern should be: all(s not in my_string for s in input_list)

l = ["abc","ghi"]
s1 = "xyzjkl"
s2 = "abcdef"

print(all(s not in s1 for s in l))  # True
print(all(s not in s2 for s in l))  # False

Answered By: Alexander L. Hayes

Answer 2

You need a list of True, False. But you were simply getting the matched items, so when you do an all on Truthy values you will get True. Instead do:

all([x not in s1 for x in l])
all([x not in s2 for x in l])

or just without list comp, because all accepts an iterable.

all(x not in s1 for x in l)
all(x not in s2 for x in l)

Answered By: SomeDude

Answer 3

I think what you want to do is:

all(x not in s1 for x in l)  # True
all(x not in s2 for x in l)  # False

Answered By: Martí

How to use all() in python?

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