why i getting IndexError: list index out of range

Question

Complete the solution so that it splits the string into pairs of two characters. If the string contains an odd number of characters then it should replace the missing second character of the final pair with an underscore (‘_’).

Examples:

‘abc’ => [‘ab’, ‘c_’]
‘abcdef’ => [‘ab’, ‘cd’, ‘ef’]

https://prnt.sc/E2sdtceLtkmF



# **My Code:**

def solution(s):
    ```n = 2
    ```sp = [s[index : index + n] for index in range(0, len(s), n)]
    
    ```if len(sp[-1]) == 1:
        sp[-1] = sp[-1] + "_"
        ```return sp
    ```else:
        ```return sp

and i geting this error:

Traceback (most recent call last):
  File "/workspace/default/tests.py", line 13, in <module>
    test.assert_equals(solution(inp), exp)
  File "/workspace/default/solution.py", line 5, in solution
    if len(sp[-1]) == 1:
IndexError: list index out of range

# pls someone help

Asked By: Giorgi Maisuradze

||

Source

Answer 1

its fixed by adding another if condition which checking sp is empty or not

def solution(s):
    n = 2
    sp = [s[index : index + n] for index in range(0, len(s), n)]

    if len(sp) == 0:
       return sp

    if len(sp[-1]) == 1:
       sp[-1] = sp[-1] + "_"
       return sp

    else:
       return sp

Answered By: Giorgi Maisuradze

Answer 2

You need to test for the possibility that the input parameter is an empty string.

def solution(s):
    n = 2
    sp = [s[index : index + n] for index in range(0, len(s), n)]
    if sp and len(sp[-1]) == 1:
        sp[-1] += '_'
    return sp

Answered By: Cobra

why i getting IndexError: list index out of range

Question:

and i geting this error:

Answers: