How to use a lambda function to sort a dictionary with a nested list?
Question:
I’ve been trying to sort a dictionary based on largest to lowest values. The dictionary is structured like this:
testing = {"third":[1,89],"first":[5,46],"second":[3,59]}
The issue I’m coming across is that I’m not entirely sure as to how I can sort this based on the second listed value, so I want to sort it based on 89, 46 and 59. Not the first 1,5,3.
The method I was currently using is:
print(sorted(testing,key=lambda x:x[1][-1]))
Which is sorting the dictionary, but not in the way I’m trying to get it to. Where second is being sorted for the first value.
I’m sure there’s a way to do this, I’m just not sure how to approach this lambda function. Any guidance would be greatly appreciate.
Answers:
sorted(testing.items(), key=lambda x: x[1][1])?
output:
[('first', [5, 46]), ('second', [3, 59]), ('third', [1, 89])]
I’ve been trying to sort a dictionary based on largest to lowest values. The dictionary is structured like this:
testing = {"third":[1,89],"first":[5,46],"second":[3,59]}
The issue I’m coming across is that I’m not entirely sure as to how I can sort this based on the second listed value, so I want to sort it based on 89, 46 and 59. Not the first 1,5,3.
The method I was currently using is:
print(sorted(testing,key=lambda x:x[1][-1]))
Which is sorting the dictionary, but not in the way I’m trying to get it to. Where second is being sorted for the first value.
I’m sure there’s a way to do this, I’m just not sure how to approach this lambda function. Any guidance would be greatly appreciate.
sorted(testing.items(), key=lambda x: x[1][1])?
output:
[('first', [5, 46]), ('second', [3, 59]), ('third', [1, 89])]