How To Get Selenium to Click Sign In Button
Question:
I’m trying to get selenium to log in to a page to scrape data. I can’t get it to click the "Sign in" button. Inspecting the button HTML gives me:
<button class="btn__primary--large from__button--floating" data-litms-control-urn="login-submit" type="submit" aria-label="Sign in">Sign in</button>
The online documentation for selenium has been very unhelpful. Does anyone know what I would use to have selenium identify and click the button? The latest unsuccessful try I executed was:
driver.find_element(By.NAME, "Sign in").click()
Answers:
You can use the following CSS_Selector:
driver.find_element(By.CSS_SELECTOR, "button[type='submit']").click()
Don’t forget to wait for the element to become clickable.
This should be done with use of WebDriverWait expected_conditions
As following
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 20)
wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button[type='submit']"))).click()
To get Selenium to click the sign in button, you would need to locate the sign in button on the page and then use Selenium’s click() method to click it.
Here is an example of how you could do this in Python:
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.example.com")
# Locate the sign in button using its CSS selector
sign_in_button = driver.find_element_by_css_selector("#sign-in-button")
# Click the sign in button
sign_in_button.click()
In this example, the find_element_by_css_selector() method is used to locate the sign in button on the page by its CSS selector. The click() method is then called on the sign_in_button element to click it.
Keep in mind that the CSS selector used in this example is just an example, and you may need to adjust it depending on the HTML structure of the sign in button on your page. You can also use other methods to locate the sign in button, such as find_element_by_id(), find_element_by_name(), or find_element_by_class_name().
You can refer to the Selenium documentation for more information and examples on locating elements and using the click() method.
Try this!
from selenium.webdriver import Keys
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
url = "https://www.linkedin.com/uas/login?session_redirect=https%3A%2F%2Fwww%2Elinkedin%2Ecom%2Fmy-items%2Fsaved-jobs%2F%3Fstart%3D0&fromSignIn=true&trk=cold_join_sign_in"
wait_5 = WebDriverWait(driver, 5)
wait_5.until(EC.element_to_be_clickable((By.XPATH, '/html/body/div/main/div[3]/div[1]/form/div[3]/button'))).click()
It would be better to use selenium-wire undetected browser with proxies!)
I’m trying to get selenium to log in to a page to scrape data. I can’t get it to click the "Sign in" button. Inspecting the button HTML gives me:
<button class="btn__primary--large from__button--floating" data-litms-control-urn="login-submit" type="submit" aria-label="Sign in">Sign in</button>
The online documentation for selenium has been very unhelpful. Does anyone know what I would use to have selenium identify and click the button? The latest unsuccessful try I executed was:
driver.find_element(By.NAME, "Sign in").click()
You can use the following CSS_Selector:
driver.find_element(By.CSS_SELECTOR, "button[type='submit']").click()
Don’t forget to wait for the element to become clickable.
This should be done with use of WebDriverWait expected_conditions
As following
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 20)
wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button[type='submit']"))).click()
To get Selenium to click the sign in button, you would need to locate the sign in button on the page and then use Selenium’s click() method to click it.
Here is an example of how you could do this in Python:
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.example.com")
# Locate the sign in button using its CSS selector
sign_in_button = driver.find_element_by_css_selector("#sign-in-button")
# Click the sign in button
sign_in_button.click()
In this example, the find_element_by_css_selector() method is used to locate the sign in button on the page by its CSS selector. The click() method is then called on the sign_in_button element to click it.
Keep in mind that the CSS selector used in this example is just an example, and you may need to adjust it depending on the HTML structure of the sign in button on your page. You can also use other methods to locate the sign in button, such as find_element_by_id(), find_element_by_name(), or find_element_by_class_name().
You can refer to the Selenium documentation for more information and examples on locating elements and using the click() method.
Try this!
from selenium.webdriver import Keys
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
url = "https://www.linkedin.com/uas/login?session_redirect=https%3A%2F%2Fwww%2Elinkedin%2Ecom%2Fmy-items%2Fsaved-jobs%2F%3Fstart%3D0&fromSignIn=true&trk=cold_join_sign_in"
wait_5 = WebDriverWait(driver, 5)
wait_5.until(EC.element_to_be_clickable((By.XPATH, '/html/body/div/main/div[3]/div[1]/form/div[3]/button'))).click()
It would be better to use selenium-wire undetected browser with proxies!)