Time interval calculation yields wrong results

Question:

I have a dataframe that looks like this:( not putting all the rows since it is alot)

               commitDate  commits  api_spec_id info_version  Days-diff  
29193 2021-03-10 10:24:56      181       156422    1.225.430          0   
29192 2021-03-10 15:14:12      181       156422    1.225.497          0   
29191 2021-03-10 18:33:18      181       156422    1.225.541          0   
29190 2021-03-11 16:14:49      181       156422    1.225.712          1   
29189 2021-03-15 10:31:03      181       156422     1.226.49          5   
29188 2021-03-15 17:11:09      181       156422    1.226.157          5   
29187 2021-03-16 12:33:34      181       156422    1.226.376          6   
29186 2021-03-17 12:54:09      181       156422    1.226.680          7   
29185 2021-03-18 15:33:44      181       156422    1.226.959          8   
29184 2021-03-22 10:38:21      181       156422    1.227.290         12   
29312 2021-12-08 08:15:07      181       156422    1.270.370        273   
29311 2021-12-14 15:20:23      181       156422    1.271.471        279   
29310 2021-12-15 17:26:35      181       156422    1.271.782        280   
29309 2021-12-17 09:01:14      181       156422     1.272.43        282   
29308 2021-12-20 17:14:55      181       156422    1.272.573        285   
29307 2021-12-23 09:39:24      181       156422    1.273.170        288  

I have been calculating the time interval between the last and the first commit date: which is 23 Dec 2021 as last, and March 3 2021 as first. However the days_diff only comes correct when I specify the basedate and not otherwise.

The code on which it works is this:

basedate = pd.Timestamp('2021-03-10')
data4['Days-diff'] = (data4['commitDate'] - basedate).dt.days

I saw this instance of wrong calculation while looking at this subset of my dataframe, and had used this code for age calculation:

g = final_api.groupby('api_spec_id')['commitDate']
final_api['Age-final'] = g.transform('last').sub(g.transform('first'))

and this:

t = pd.to_datetime(final_api['commitDate'])
final_api['Days_difference'] = t.sub(t.groupby(final_api['api_spec_id']).transform('min')).dt.days

The Age should come as 289 days but it is coming as 525 days when I use these code above. For days_difference as well my output comes like this:

            commitDate  Days-diff        Age-final  Days_difference
29193 2021-03-10 10:24:56          0 67 days 22:17:54              236
29192 2021-03-10 15:14:12          0 67 days 22:17:54              237
29191 2021-03-10 18:33:18          0 67 days 22:17:54              237
29190 2021-03-11 16:14:49          1 67 days 22:17:54              238
29189 2021-03-15 10:31:03          5 67 days 22:17:54              241

which is wrong since it is supposed to start from 0 for days_difference. I am lost as to where I am going wrong.any help will be appreciated.

Asked By: Brie MerryWeather

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Answers:

In the code that you have shown, it seems like you are trying to calculate the number of days between the first and the last commit date for each api_spec_id group.

To do this, you can use the groupby method to group the dataframe by api_spec_id and then use the agg method to calculate the number of days between the first and the last commit date for each group.

Here is an example of how you can do this:

# Group the dataframe by api_spec_id
g = final_api.groupby('api_spec_id')

# Use the agg method to calculate the number of days between the first and last commit date
# for each group.
final_api['Age-final'] = g.commitDate.agg(lambda x: x.max() - x.min())

This code will calculate the number of days between the first and last commit date for each group and store the result in the Age-final column of the final_api dataframe.

To calculate the difference between each commit date and the first commit date for the corresponding api_spec_id group, you can use the transform method in combination with the min function.

Here is an example of how you can do this:

# Get the datetime values of the commitDate column
t = pd.to_datetime(final_api['commitDate'])

# Group the datetime values by api_spec_id and calculate the minimum value for each group
# using the min function
first_commit_date = t.groupby(final_api['api_spec_id']).transform('min')

# Calculate the difference between each commit date and the first commit date for the corresponding
# api_spec_id group using the transform method.
final_api['Days_difference'] = t.sub(first_commit_date).dt.days

This code will calculate the difference between each commit date and the first commit date for the corresponding api_spec_id group and store the result in the Days_difference column of the final_api dataframe.

Answered By: A.S
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