remove even elements from a list. Showing list index out of range

Question

image
please refer to the image.
I want to create a list(say [1,2,3,4,5]). The code checks the divisibility by 2 of every element of the list one by one. if it is divisible by 2, it removes the those elements and returns a list of odd numbers . Please try to keep the code as simple as possible as i am just a beginner….

Asked By: Dweep Desai

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Answer 1

l = [1,2,3,4,5]
x = len(l)
new_l = []
for a in range(x):
    if l[a]%2!=0:
        new_l.append(l[a])
new_l

Use the above code instead of removing elements from list create a new one.

Answered By: rishabh11336

Answer 2

I took a look at the image and couldn’t figure out much. Going by your definition

l = [1,2,3,4]

for i in l:
    if i % 2 == 0:  # check if i is divisible by 2
         l.remove(i)  # remove the item if the number passes above check.

Answered By: Sid

Answer 3

It’s a lot easier and more Pythonic to build a new list of the odd numbers than it is to modify the original list to remove the even numbers.

If you understand list comprehensions, there’s a simple answer.

l = [1, 2, 3, 4, 5]
l2 = [x for x in l if x%2 == 1]
print(l2)

You can also do it imperatively:

l = [1, 2, 3, 4, 5]
l2 = []
for x in l:
    if x%2 == 1:
        l2.append(x)
print(l2)

Either solution will print [1, 3, 5].

Answered By: George V. Reilly

Answer 4

The problem with your code is that once you remove the even number from the list, It reduces the length of the list. So in the second iteration of your code, 2 is removed from the list l = [1,2,3,4,5] which modifies the list l to [1,3,4,5], so now, the length of the list is 4 instead of 5. But the for loop, which will run for the values "0, 1, 2, 3, 4" (because of variable x, which is 5), your code produces that error.
To solve this error, you can create a new list and append the even numbers in it.

Answered By: Nitin Rattu

remove even elements from a list. Showing list index out of range

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