Convert input string contain font in list

Question

I want to convert a input text " " contain in the font list "original":

text = input("Enter text: ")

#Enter text:  

original = [" ",
            " 0123456789",
            " ",
            "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"]

replace = ["ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"]

originalMap = original[0]
replaceMap = replace[0]
result = ""
for i in text:
    if i in originalMap:
        result += replaceMap[originalMap.index(i)]
                
    else:   
        result += i

print("Converted: " +result)

#Converted: APPLE

But I can’t convert with another font in the list "original" such as , , …

Could anyone help me on this?

Asked By: Kimhab

||

Source

Answer 1

You need to add all the possible mappings in one structure, from each letter of the 4 fonts to the classic one

Use a dict for that. And give 4 times the mapping: one font > classic font, that will make a dict of 62*4=248 mappings

text = "A ! "

original = [" ",
            " 0123456789",
            " ",
            "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"]
replaceAlphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"

originalMap = {}
for alphabet in original:
    originalMap.update(dict(zip(alphabet, replaceAlphabet)))

Then for the use, use dict.get, it’ll search for the value in the dict, if it don’t find it it’ll use the default value, set char too for the default value => pick the corresponding value OR use the key itself

result = "".join(originalMap.get(char, char) for char in text)

print("Converted: " + result)
# Converted: APPLE!012

Answered By: azro

Answer 2

You can use the str.translate function to replace characters:

original = [" ",
            " 0123456789",
            " ",
            "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"]

# This can just be a string, no need for it to be a list of strings
replace = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"

# Create a mapping from char codes to the replacment
mapping = {ord(char):replace[index] for font in original for index,char in enumerate(font)}

# Use the translate method to modify each character according to the map
print("Converted:", input().translate(mapping))

See the documentation to learn more about str.translate

Answered By: mousetail

Answer 3

I think you’re hoping to convert the input to each of three different fonts. In which case:

original = " "

alternative = [
    " ",
    " ",
    "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
]

text = ' '

for a in alternative:
    t = ''
    for c in text:
        if (i := original.find(c)) >= 0:
            t += a[i]
        else:
            t += c
    print(t)

Output:

 
 
APPLE

Answered By: Cobra

Convert input string contain font in list

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