Given a character of the alphabet I want to compute and print an integer value as a result

Question

Alphabet combines alphabet in lower case and upper case : ab…zAB…Z

If input character is ‘a’ expected result is 1.

If input character is ‘b’ expected result is 2.

If input character is ‘z’ expected result is 26.

If input character is ‘A’ expected result is 27.

If input character is ‘B’ expected result is 28.

If input character is ‘Z’ expected result is 52.

I’ve tried the above code that works but I wonder if a simplest solution exists.

c = input()
if "a" <= c <= "z":
   print (ord(c)-ord("a")+1)
elif "A" <= c <= "Z":
    print (ord(c)-ord("A")+27)

Asked By: dude

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Source

Answer 1

You can use ascii_letters provided by the string module which consists of the lower-case alphabet followed by the upper-case alphabet and find the index of your letter.

from string import ascii_letters

c = input()
print(ascii_letters.index(c)+1)

You could even prepare the "lookup table" with a first unused character, that will avoid to add 1 when calling index().

from string import ascii_letters

table = "." + ascii_letters
c = input()
print(table.index(c))

Answered By: 0x0fba

Answer 2

use the isupper() and islower() methods to check if character is upper or lower

c = input()
if c.islower():
    print(ord(c)-ord('a')+1)
elif c.isupper():
    print(ord(c)-ord('A')+27)

Answered By: THUNDER 07

Given a character of the alphabet I want to compute and print an integer value as a result

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