I want to Remove a print function if Someone choose another option in python

Question

I have three print function in python basically these a option 1 2 3 if someone choose 1 after that when it again come to these steps beacause it is infinite loop i want to remove option 3 from there basically i want to remove print function.
Please help me .
Thanks in Advance .
Is it ok if i use a if else here !!!!!!

this is portion where i want to do that

In this i want third print removed after if Someone chose choice 1

self.blackjack = False
print(f" Press 1 For Hit a New Card ")
print(" Press 2 For Stand ")
print(" Press 3 for Double ")
choice = int(input(" Enter Your Choice: "))
if choice == 1:

    running = self.hitTheCard()
elif choice == 2:
    self.stand()
    running = False
elif choice == 3:
    self.betAmount *= 2
    running = self.hitTheCard()
    self.player.displayCardInHand()
    if running:
        self.stand()
        running = False
else:
    print(" Invalid choice given try again.")

Feel free give me advices please

Asked By: Simranjeet Singh

||

Source

Answer 1

Put your options in a dictionary; then you can loop over the dictionary to display the available options, and delete them from the dictionary when you want them to no longer be available.

options = {
    '1': ("Hit a New Card", self.hitTheCard),
    '2': ("Stand", self.stand),
    '3': ("Double", self.double),
}

while True:
    for opt, (desc, _func) in options.items():
        print(f"Press {opt} for {desc}")
    choice = input("Enter your choice: ")
    if choice not in options:
        print("Invalid choice, try again.")
        continue
    _desc, func = options[choice]
    del options[choice]
    func()

Answered By: Samwise

I want to Remove a print function if Someone choose another option in python

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