Range in For-loop Python
Question:
for i in range(4,7):
i=i+3
print("Hello")
Kindly help me with the well explained output for this program.
Answers:
This code uses a for loop to iterate over the numbers in the range 4 to 7 (inclusive). For each number i in the loop, it adds 3 to i and then prints the string "Hello".
Here is how the code will execute:
- The for loop starts with
i=4.
i is incremented by 3, so i=7.- The string "Hello" is printed.
- The for loop continues with
i=5.
i is incremented by 3, so i=8.- The string "Hello" is printed.
- The for loop continues with
i=6.
- i is incremented by 3, so
i=9.
- The string "Hello" is printed.
- The for loop ends because all numbers in the range 4 to 7 have been processed.
Therefore, this code will print the string "Hello" three times.
Note that the assignment of the variable i inside the loop does not make sense because at each iteration of the loop, the variable i is updated
It is going to print Hello three times.
In every loop it will set the value of loop counter to loop counter + 3.
And then print Hello. But after every iteration the loop counter will be overwritten by the for loop.
So i=i+3 is redundant.
for i in range(4,7):
i=i+3
print("Hello")
Kindly help me with the well explained output for this program.
This code uses a for loop to iterate over the numbers in the range 4 to 7 (inclusive). For each number i in the loop, it adds 3 to i and then prints the string "Hello".
Here is how the code will execute:
- The for loop starts with
i=4. iis incremented by 3, soi=7.- The string "Hello" is printed.
- The for loop continues with
i=5. iis incremented by 3, soi=8.- The string "Hello" is printed.
- The for loop continues with
i=6. - i is incremented by 3, so
i=9. - The string "Hello" is printed.
- The for loop ends because all numbers in the range 4 to 7 have been processed.
Therefore, this code will print the string "Hello" three times.
Note that the assignment of the variable i inside the loop does not make sense because at each iteration of the loop, the variable i is updated
It is going to print Hello three times.
In every loop it will set the value of loop counter to loop counter + 3.
And then print Hello. But after every iteration the loop counter will be overwritten by the for loop.
So i=i+3 is redundant.