Remove items out of a python tuple

Question

I have a list of tuples with word frequencies and a list of words to eliminate. How to avoid loops and delete tuples from a list?

data = [('the',23),('for',15),('so',10),('micro',10),('if',10),('macro',10)]
words = ['so','is','for','if'] # unique
indice =[]

# %%
for ii in range(len(data)):
    for jj in range(len(words)):
        if words[jj]==data[ii][0]:
            print(words[jj]+ ': found')
            indice.append(ii)

# del data[indice]      # doesn't work
# data.remove(indice)   # doesn't work

Asked By: cbeu-user-99263

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Source

Answer 1

I would transform the word list to a set for faster lookups, and then use a list comprehension:

wordset = set(wordset)
[item for item in data if item[0] not in wordset]

This outputs:

[('the', 23), ('micro', 10), ('macro', 10)]

Answered By: BrokenBenchmark

Answer 2

This is precisely what the built-in filter() function is useful for.

No explicit loop here.

e.g.,

data = [('the',23),('for',15),('so',10),('micro',10),('if',10),('macro',10)]
words = ['so','is','for','if']

indice = list(filter(lambda x: x[0] not in words, data))

print(indice)

Output:

[('the', 23), ('micro', 10), ('macro', 10)]

As has been pointed out in an earlier comment, words should be a set for enhanced performance

Answered By: Fred

Remove items out of a python tuple

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