Is there any function to check the location of the last date element in pandas dataframe?
Question:
The sample data is like:
Empty header
‘2/01/2011’
‘3/01/2011’
‘4/01/2011’
‘5.222’
‘6.214’
‘1.34266’
The data above are all strings.
My expected outcome is
Date
Value
2/01/2011
5.222
3/01/2011
6.214
4/01/2011
1.34266
The ‘Date’ variable should be in date format, ‘Value’ variable is in float.
Answers:
Example
s = pd.Series(['2/01/2011', '3/01/2011', '4/01/2011', '5.222', '6.214', '1.34266'])
s
0 2/01/2011
1 3/01/2011
2 4/01/2011
3 5.222
4 6.214
5 1.34266
dtype: object
Code
cond1 = s.str.contains(r'd+/')
out = (s.groupby(cond1, sort=False).apply(lambda x: pd.Series(list(x)))
.unstack(level=0).set_axis(['Date', 'Value'], axis=1))
out
Date Value
0 2/01/2011 5.222
1 3/01/2011 6.214
2 4/01/2011 1.34266
The sample data is like:
| Empty header |
|---|
| ‘2/01/2011’ |
| ‘3/01/2011’ |
| ‘4/01/2011’ |
| ‘5.222’ |
| ‘6.214’ |
| ‘1.34266’ |
The data above are all strings.
My expected outcome is
| Date | Value |
|---|---|
| 2/01/2011 | 5.222 |
| 3/01/2011 | 6.214 |
| 4/01/2011 | 1.34266 |
The ‘Date’ variable should be in date format, ‘Value’ variable is in float.
Example
s = pd.Series(['2/01/2011', '3/01/2011', '4/01/2011', '5.222', '6.214', '1.34266'])
s
0 2/01/2011
1 3/01/2011
2 4/01/2011
3 5.222
4 6.214
5 1.34266
dtype: object
Code
cond1 = s.str.contains(r'd+/')
out = (s.groupby(cond1, sort=False).apply(lambda x: pd.Series(list(x)))
.unstack(level=0).set_axis(['Date', 'Value'], axis=1))
out
Date Value
0 2/01/2011 5.222
1 3/01/2011 6.214
2 4/01/2011 1.34266