How do I create a datetime in Python from milliseconds?
Question:
How do I create a datetime in Python from milliseconds? I can create a similar Date
object in Java by java.util.Date(milliseconds)
.
Allocates a Date object and initializes it to represent the specified number of milliseconds since the standard base time known as "the epoch", namely January 1, 1970, 00:00:00 GMT.
Answers:
Just convert it to timestamp
datetime.datetime.fromtimestamp(ms/1000.0)
What about this? I presume it can be counted on to handle dates before 1970 and after 2038.
target_datetime_ms = 200000 # or whatever
base_datetime = datetime.datetime(1970, 1, 1)
delta = datetime.timedelta(0, 0, 0, target_datetime_ms)
target_datetime = base_datetime + delta
as mentioned in the Python standard lib:
fromtimestamp() may raise ValueError, if the timestamp is out of the
range of values supported by the platform C localtime() or gmtime()
functions. It’s common for this to be restricted to years in 1970
through 2038.
Very obviously, this can be done in one line:
target_dt = datetime(1970, 1, 1) + timedelta(milliseconds=target_dt_ms)
… not only was this obvious from my answer, but the 2015 comment by jfs is also highly misleading, because it calls the variable utc_time
.
Er no: it’s not "time", it’s datetime
, and it’s most definitely NOT UTC. The datetime
with which we’re concerned here is a "timezone-naive" datetime
, as opposed to a timezone-aware datetime
. Therefore definitely NOT UTC.
Search on this if you’re not familiar with the issue.
Bit heavy because of using pandas but works:
import pandas as pd
pd.to_datetime(msec_from_java, unit='ms').to_pydatetime()
import pandas as pd
Date_Time = pd.to_datetime(df.NameOfColumn, unit='ms')
Converting millis to datetime (UTC):
import datetime
time_in_millis = 1596542285000
dt = datetime.datetime.fromtimestamp(time_in_millis / 1000.0, tz=datetime.timezone.utc)
How do I create a datetime in Python from milliseconds? I can create a similar Date
object in Java by java.util.Date(milliseconds)
.
Allocates a Date object and initializes it to represent the specified number of milliseconds since the standard base time known as "the epoch", namely January 1, 1970, 00:00:00 GMT.
Just convert it to timestamp
datetime.datetime.fromtimestamp(ms/1000.0)
What about this? I presume it can be counted on to handle dates before 1970 and after 2038.
target_datetime_ms = 200000 # or whatever
base_datetime = datetime.datetime(1970, 1, 1)
delta = datetime.timedelta(0, 0, 0, target_datetime_ms)
target_datetime = base_datetime + delta
as mentioned in the Python standard lib:
fromtimestamp() may raise ValueError, if the timestamp is out of the
range of values supported by the platform C localtime() or gmtime()
functions. It’s common for this to be restricted to years in 1970
through 2038.
Very obviously, this can be done in one line:
target_dt = datetime(1970, 1, 1) + timedelta(milliseconds=target_dt_ms)
… not only was this obvious from my answer, but the 2015 comment by jfs is also highly misleading, because it calls the variable utc_time
.
Er no: it’s not "time", it’s datetime
, and it’s most definitely NOT UTC. The datetime
with which we’re concerned here is a "timezone-naive" datetime
, as opposed to a timezone-aware datetime
. Therefore definitely NOT UTC.
Search on this if you’re not familiar with the issue.
Bit heavy because of using pandas but works:
import pandas as pd
pd.to_datetime(msec_from_java, unit='ms').to_pydatetime()
import pandas as pd
Date_Time = pd.to_datetime(df.NameOfColumn, unit='ms')
Converting millis to datetime (UTC):
import datetime
time_in_millis = 1596542285000
dt = datetime.datetime.fromtimestamp(time_in_millis / 1000.0, tz=datetime.timezone.utc)