AttributeError: 'Query' object has no attribute 'is_clause_element' when joining table with query
Question:
AttributeError: ‘Query’ object has no attribute ‘is_clause_element’ when joining table with query
I have a query that counts the amount of keywords a company has and then sorts them by the amount of keywords they have.
query_company_ids = Session.query(enjordplatformCompanyToKeywords.company_id.label("company_id"),func.count(enjordplatformCompanyToKeywords.keyword_id)).group_by(enjordplatformCompanyToKeywords.company_id).order_by(desc(func.count(enjordplatformCompanyToKeywords.keyword_id))).limit(20)
I then want to get information about these companies like image, title, info etc and send it to the frontend (this is done later by looping through companies_query).
Though I have trouble in building the connection between the query_company_ids query and enjordplatformCompanies table.
I have tried two ways of doing this:
- companies_query = Session.query(enjordplatformCompanies, query_company_ids).filter(enjordplatformCompanies.id == query_company_ids.company_id).all()
- companies_query = Session.query(enjordplatformCompanies, query_company_ids).join( query_company_ids, query_company_ids.c.company_id == enjordplatformCompanies.id).all()
But both of them result in the error: AttributeError: ‘Query’ object has no attribute ‘is_clause_element’
Question
How can I join the query_company_ids query and enjordplatformCompanies table?
Thanks
Here are the table definitions
class enjordplatformCompanies(Base):
__tablename__ = "enjordplatform_companies"
id = Column(Integer, primary_key=True, unique=True)
name = Column(String)
about = Column(String)
image = Column(String)
website = Column(String)
week_added = Column(Integer)
year_added = Column(Integer)
datetime_added = Column(DateTime)
created_by_userid = Column(Integer)
company_type = Column(String)
contact_email=Column(String)
adress=Column(String)
city_code=Column(String)
city=Column(String)
class enjordplatformCompanyToKeywords(Base):
__tablename__ = "enjordplatform_company_to_keywords"
id = Column(Integer, primary_key=True, unique=True)
company_id = Column(Integer,ForeignKey("enjordplatform_companies.id"))
keyword_id = Column(Integer,ForeignKey("enjordplatform_keywords.id"))
Answers:
I copied your example query above and was getting a lot of weird errors until I realized you use Session
instead of session
. I guess make sure you are using an instance instead of the class or sessionmaker.
Below I create an explicit subquery()
to get the company id paired with its keyword count and then I join the companies class against that, applying the order and limit to the final query.
with Session(engine) as session, session.begin():
subq = session.query(
enjordplatformCompanyToKeywords.company_id,
func.count(enjordplatformCompanyToKeywords.keyword_id).label('keyword_count')
).group_by(
enjordplatformCompanyToKeywords.company_id
).subquery()
q = session.query(
enjordplatformCompanies,
subq.c.keyword_count
).join(
subq,
enjordplatformCompanies.id == subq.c.company_id
).order_by(
desc(subq.c.keyword_count)
)
for company, keyword_count in q.limit(20).all():
print (company.name, keyword_count)
This isn’t the exact method but explains the intention of calling .subquery()
above:
subquery
AttributeError: ‘Query’ object has no attribute ‘is_clause_element’ when joining table with query
I have a query that counts the amount of keywords a company has and then sorts them by the amount of keywords they have.
query_company_ids = Session.query(enjordplatformCompanyToKeywords.company_id.label("company_id"),func.count(enjordplatformCompanyToKeywords.keyword_id)).group_by(enjordplatformCompanyToKeywords.company_id).order_by(desc(func.count(enjordplatformCompanyToKeywords.keyword_id))).limit(20)
I then want to get information about these companies like image, title, info etc and send it to the frontend (this is done later by looping through companies_query).
Though I have trouble in building the connection between the query_company_ids query and enjordplatformCompanies table.
I have tried two ways of doing this:
- companies_query = Session.query(enjordplatformCompanies, query_company_ids).filter(enjordplatformCompanies.id == query_company_ids.company_id).all()
- companies_query = Session.query(enjordplatformCompanies, query_company_ids).join( query_company_ids, query_company_ids.c.company_id == enjordplatformCompanies.id).all()
But both of them result in the error: AttributeError: ‘Query’ object has no attribute ‘is_clause_element’
Question
How can I join the query_company_ids query and enjordplatformCompanies table?
Thanks
Here are the table definitions
class enjordplatformCompanies(Base):
__tablename__ = "enjordplatform_companies"
id = Column(Integer, primary_key=True, unique=True)
name = Column(String)
about = Column(String)
image = Column(String)
website = Column(String)
week_added = Column(Integer)
year_added = Column(Integer)
datetime_added = Column(DateTime)
created_by_userid = Column(Integer)
company_type = Column(String)
contact_email=Column(String)
adress=Column(String)
city_code=Column(String)
city=Column(String)
class enjordplatformCompanyToKeywords(Base):
__tablename__ = "enjordplatform_company_to_keywords"
id = Column(Integer, primary_key=True, unique=True)
company_id = Column(Integer,ForeignKey("enjordplatform_companies.id"))
keyword_id = Column(Integer,ForeignKey("enjordplatform_keywords.id"))
I copied your example query above and was getting a lot of weird errors until I realized you use Session
instead of session
. I guess make sure you are using an instance instead of the class or sessionmaker.
Below I create an explicit subquery()
to get the company id paired with its keyword count and then I join the companies class against that, applying the order and limit to the final query.
with Session(engine) as session, session.begin():
subq = session.query(
enjordplatformCompanyToKeywords.company_id,
func.count(enjordplatformCompanyToKeywords.keyword_id).label('keyword_count')
).group_by(
enjordplatformCompanyToKeywords.company_id
).subquery()
q = session.query(
enjordplatformCompanies,
subq.c.keyword_count
).join(
subq,
enjordplatformCompanies.id == subq.c.company_id
).order_by(
desc(subq.c.keyword_count)
)
for company, keyword_count in q.limit(20).all():
print (company.name, keyword_count)
This isn’t the exact method but explains the intention of calling .subquery()
above:
subquery