How to accept an ascii character with python re (regex)

Question

I have a regex that controls a password so that it contains an upper case, a lower case, a number, a special character and minimum 8 characters.

regex is:

regex_password = r"^(?=.*[a-z])(?=.*[A-Z])(?=.*[W]).{8,}$"

I use in this function:

def password_validator(password):
    #REGEX PASSWORD : minimum 8 characters, 1 lowercase, 1 uppercase, 1 special caracter
    regex_password = r"^(?=.*[a-z])(?=.*[A-Z])(?=.*[W]).{8,}$"

    if not re.match(regex_password, password):
        raise ValueError("""value is not a valid password""")
    return password

However, the use of "²" raises me an error, however, this same regex with a Javascript front-end validation, or on different regex validation site,works.

The problem is possible the ascii, so how can i do for python accept the ascii character in regex ?

Asked By: fchancel

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Source

Answer 1

From the documentation:

W

Matches any character which is not a word character. This is the opposite of w. If the ASCII flag is used this becomes the equivalent of [^a-zA-Z0-9_]. If the LOCALE flag is used, matches characters which are neither alphanumeric in the current locale nor the underscore.

Other implementations may interpret w as referring to only ASCII alphanumeric characters and underscore by default and W by extension contains every non-ASCII alphanumeric characters as well as non-alphanumeric characters.

Possible solutions:

Spell it out:

regex_password = r"^(?=.*[a-z])(?=.*[A-Z])(?=.*[^a-zA-Z0-9_]).{8,}$"

Or use the re.ASCII flag:

if not re.match(regex_password, password, flags=re.ASCII):

Either one of these changes should give you the results you need.

Answered By: Jasmijn

How to accept an ascii character with python re (regex)

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