create a list with pairs from a column in pandas
Question:
I have a column with pairs like these
id
pairs
1
a,b,c
2
b,d
3
a
4
d,e
5
g,h
6
a,h
7
f,d
8
o,p
I want to have these output
[('ca', 'b'), ('a', 'c'),('b','c'),('b','d'),('d','e'),('g','h'),('a','h'),('f','d'),('o','p')]
I did these, but not the desired solution
for pair in combinations([df['pairs']], 2):
print(pairs)
any suggestions?
Answers:
try this
pairs = []
for row in df['pairs']:
row_list = row.split(',')
for pair in combinations(row_list, 2):
pairs.append(pair)
print(pairs)
I have a column with pairs like these
| id | pairs |
|---|---|
| 1 | a,b,c |
| 2 | b,d |
| 3 | a |
| 4 | d,e |
| 5 | g,h |
| 6 | a,h |
| 7 | f,d |
| 8 | o,p |
I want to have these output
[('ca', 'b'), ('a', 'c'),('b','c'),('b','d'),('d','e'),('g','h'),('a','h'),('f','d'),('o','p')]
I did these, but not the desired solution
for pair in combinations([df['pairs']], 2):
print(pairs)
any suggestions?
try this
pairs = []
for row in df['pairs']:
row_list = row.split(',')
for pair in combinations(row_list, 2):
pairs.append(pair)
print(pairs)