Is it possible to print the match of a re.search() used in an if statement?
Question:
I need to keep my regex search in an if statement. Is it possible to get the match of my re.search() like this?
if re.search(regex,string):
print(match)
Answers:
It is possible like this:
if match := re.search(regex,string):
print(match)
Python-3.8+ required for assignment expressions.
import re
my_string = "abcdefcddd"
if re.search('c', my_string):
print("A match found.")
else:
print('No match')
#or
found = re.search('c', my_string)
print(found.group())
print(found.span()) #index of the first match
My guess you may need re.findall() or its sister re.finditer() if you want to find all the regex matches.
matches = re.findall('c', my_string)
print(matches)
matches = re.finditer('c', my_string)
for match in matches:
print(match)
Maybe check and see what exactly you need. Python documentation should help.
I need to keep my regex search in an if statement. Is it possible to get the match of my re.search() like this?
if re.search(regex,string):
print(match)
It is possible like this:
if match := re.search(regex,string):
print(match)
Python-3.8+ required for assignment expressions.
import re
my_string = "abcdefcddd"
if re.search('c', my_string):
print("A match found.")
else:
print('No match')
#or
found = re.search('c', my_string)
print(found.group())
print(found.span()) #index of the first match
My guess you may need re.findall() or its sister re.finditer() if you want to find all the regex matches.
matches = re.findall('c', my_string)
print(matches)
matches = re.finditer('c', my_string)
for match in matches:
print(match)
Maybe check and see what exactly you need. Python documentation should help.