Get end of next month
Question:
There is a date like this:
Timestamp('2020-10-17 00:00:00')
How can I get the end of next month?
The output should be like this:
Timestamp('2020-11-30 00:00:00')
I tried rrule
but it does not work correctly.
My code:
import pandas as pd
from datetime import date
from dateutil.rrule import rrule, MONTHLY
start_date = date(2020, 9, 17)
end_date = date(2020, 10, 31)
for d in rrule(MONTHLY, dtstart=start_date, until=end_date):
t = pd.Timestamp(d)
print(t)
The output:
2020-09-17 00:00:00
2020-10-17 00:00:00
I am going to get end of month.
Answers:
With beautiful-date, you could do:
from beautiful_date import D, months, day, days
last_day_of_the_month = D.today() + 1 * months + 1 * day - 1 * days
This takes the current day (D.today()
), goes to the next month (+ 1 * months
), goes to the first day of the next month (+ 1 * day
), and goes one day back, i.e. last day of the current month (- 1 * days
)
And you can easily convert it to datetime:
last_day_of_the_month[0:0]
You could do it like this:
import pandas as pd
from datetime import datetime, date
date = date(2020, 10, 17)
last_day_of_next_month = pd.Timestamp(datetime.datetime(date.year, ((date.month+2) % 12), 1) - datetime.timedelta(days=1))
Basically, this just created a new date at the first day of the month after next and subtracts one day to get the last day of the next month.
EDIT:
This can be done more cleanly by using pandas DateOffset
s as mentioned in the comments and by another answer:
import pandas as pd
from datetime import date
date = date(2020, 10, 17)
last_day_of_next_month = pd.Timestamp(date) + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd(0)
in my case, change first day of next 2 month.
and then minus 1 day.
i also use this in java.
sample code
import pandas as pd
t = pd.Timestamp('2020-10-17 00:00:00')
t = t.replace(day=1)
answer = t + pd.DateOffset(months=2) + pd.DateOffset(days=-1)
In addition to the other’s answers, you can also use calender
module to get the last day of next month, as follows:
import pandas as pd
from datetime import date
import calendar
def get_nextmonth(d):
nextmonth_lastday = calendar.monthrange(d.year, d.month+1)[1] # this return first and last day of the given month, such as (0, 30)
return date(d.year, d.month+1, nextmonth_lastday)
start_date = date(2020, 9, 17)
print(get_nextmonth(start_date))
# 2020-10-31
Dateutil also works:
I set the days to 1, go two months further, and go one day back.
#pip install python-dateutil
from datetime import date
from dateutil.relativedelta import relativedelta
DAY = relativedelta(days=+1)
MONTH = relativedelta(months=+1)
first_date = date(2020, 10, 17).replace(day=1)
print(first_date + 2 * MONTH - DAY)
Output:
2020-11-30
I would do like this:
from datetime import date,timedelta
start_date = date(2020, 9, 17)
last_day_month=date(start_date.year,start_date.month+1,1)-timedelta(days=1)
Use pandas vectored way which is fast for large amounts of data.
import pandas as pd
ts = pd.Timestamp(2022, 1, 15)
ts + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd(0) -->
Out: Timestamp('2022-02-28 00:00:00')
ts = pd.Timestamp(2022, 1, 31)
ts + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd(0) --> putting 0 to get same month last date though it was last date
Out: Timestamp('2022-02-28 00:00:00')
ts = pd.Timestamp(2022, 1, 31)
ts + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd()
Out: Timestamp('2022-03-31 00:00:00')
There is a date like this:
Timestamp('2020-10-17 00:00:00')
How can I get the end of next month?
The output should be like this:
Timestamp('2020-11-30 00:00:00')
I tried rrule
but it does not work correctly.
My code:
import pandas as pd
from datetime import date
from dateutil.rrule import rrule, MONTHLY
start_date = date(2020, 9, 17)
end_date = date(2020, 10, 31)
for d in rrule(MONTHLY, dtstart=start_date, until=end_date):
t = pd.Timestamp(d)
print(t)
The output:
2020-09-17 00:00:00
2020-10-17 00:00:00
I am going to get end of month.
With beautiful-date, you could do:
from beautiful_date import D, months, day, days
last_day_of_the_month = D.today() + 1 * months + 1 * day - 1 * days
This takes the current day (D.today()
), goes to the next month (+ 1 * months
), goes to the first day of the next month (+ 1 * day
), and goes one day back, i.e. last day of the current month (- 1 * days
)
And you can easily convert it to datetime:
last_day_of_the_month[0:0]
You could do it like this:
import pandas as pd
from datetime import datetime, date
date = date(2020, 10, 17)
last_day_of_next_month = pd.Timestamp(datetime.datetime(date.year, ((date.month+2) % 12), 1) - datetime.timedelta(days=1))
Basically, this just created a new date at the first day of the month after next and subtracts one day to get the last day of the next month.
EDIT:
This can be done more cleanly by using pandas DateOffset
s as mentioned in the comments and by another answer:
import pandas as pd
from datetime import date
date = date(2020, 10, 17)
last_day_of_next_month = pd.Timestamp(date) + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd(0)
in my case, change first day of next 2 month.
and then minus 1 day.
i also use this in java.
sample code
import pandas as pd
t = pd.Timestamp('2020-10-17 00:00:00')
t = t.replace(day=1)
answer = t + pd.DateOffset(months=2) + pd.DateOffset(days=-1)
In addition to the other’s answers, you can also use calender
module to get the last day of next month, as follows:
import pandas as pd
from datetime import date
import calendar
def get_nextmonth(d):
nextmonth_lastday = calendar.monthrange(d.year, d.month+1)[1] # this return first and last day of the given month, such as (0, 30)
return date(d.year, d.month+1, nextmonth_lastday)
start_date = date(2020, 9, 17)
print(get_nextmonth(start_date))
# 2020-10-31
Dateutil also works:
I set the days to 1, go two months further, and go one day back.
#pip install python-dateutil
from datetime import date
from dateutil.relativedelta import relativedelta
DAY = relativedelta(days=+1)
MONTH = relativedelta(months=+1)
first_date = date(2020, 10, 17).replace(day=1)
print(first_date + 2 * MONTH - DAY)
Output:
2020-11-30
I would do like this:
from datetime import date,timedelta
start_date = date(2020, 9, 17)
last_day_month=date(start_date.year,start_date.month+1,1)-timedelta(days=1)
Use pandas vectored way which is fast for large amounts of data.
import pandas as pd
ts = pd.Timestamp(2022, 1, 15)
ts + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd(0) -->
Out: Timestamp('2022-02-28 00:00:00')
ts = pd.Timestamp(2022, 1, 31)
ts + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd(0) --> putting 0 to get same month last date though it was last date
Out: Timestamp('2022-02-28 00:00:00')
ts = pd.Timestamp(2022, 1, 31)
ts + pd.offsets.DateOffset(months=1) + pd.offsets.MonthEnd()
Out: Timestamp('2022-03-31 00:00:00')