Write a function called write_nums() that outputs the first positive n numbers to a txt file called nums.txt

Question

I have to print first n positive numbers for ex if its first 10 positive numbers then the output should be as follows

it should print the first 10 numbers in 10 lines but my output is as follows:

how do i delete the 11th line?

this is my code

def write_nums(n):
  with open("nums.txt", 'w') as fp:
    for i in range (1,11):
     fp.writelines(str(i)+"n")   
pass
if __name__ == "__main__":
  write_nums(10) 
  # writes out the first 10 positive numbers to nums.txt

Asked By: mo10

||

Source

Answer 1

A very crude way of doing so can be by adding an if else statement for the last run of the loop

def write_nums(n):
  with open("nums.txt", 'w') as fp:
    for i in range (1,n+1):
      if i != n:
        fp.writelines(str(i)+"n")
      else :
        fp.writelines(str(i))   
pass
if __name__ == "__main__":
  write_nums(10) 
  # writes out the first 10 positive numbers to nums.txt

I am not sure if this is the best way to do it, but it will get the code working the way you want it

Answered By: Prityush bansal

Write a function called write_nums() that outputs the first positive n numbers to a txt file called nums.txt

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