How do I get find a word that contains some specific letter AND one in particular (using regex)?
Question:
Hello everyone and thank you in advance,
I am trying to get a all the words in the following list except for "motiu" and "diomar" using regex and python:
amfora
difamador
difamar
dimorf
dofi
fada
far
farao
farda
fiar
fiord
fira
firar
firma
for
motiu
diomar
The word must not contain a letter outside the list [diomarf], but it must contain an "f"
I don’t know much about regex…I have tried with some, they are getting more complex but I haven’t got the solution yet. Some of the expressions I have tried with are:
> (?:.*f)(?:.*[diomarf])
> (?:.*[diomarf])(?:.*f)
> (?:((?:f)+)(?:[diomarf])*)
> (?:((?:[diomarf])+)(?:f)*)
> (?:((?:[diomarf])*)((?:f)+))
> (?:(((?:f)+)((?:[diomarf])*)))
> (?:((?:f)+((?:[diomarf])*)))
The expression with which I think I got the closest result is:
(?:(((?:f)+)((?:[diomarf])*)))
But it only checks from the first f of the word, for example, for "dimorf" I am only getting the last "f"
Answers:
^f[diomarf]*$|^[diomarf]*f[diomarf]*$|^[diomarf]*f$
Explanation:
^f[diomarf]*$ : A string either starts with f and then has any number of characters from this list [diomarf] (including 0!)
OR
^[diomarf]*f[diomarf]*$ the string has f somewhere in the middle
OR
^[diomarf]*f$ f at the end
The previous solution I proposed fails when disallowed characters are added to the end of the string (for example diomarfg).
Old solution for reference:
(?=[diomarf]).*f.*
Explanation:
(?=[diomarf]) – use positive lookahead to assert that at any point in the string one of the allowed letters is matched.
.*f.* – make sure that the letter f is somewhere in the string.
You can write the pattern as:
^[diomar]*f[diomarf]*$
Explanation
^ Start of string[diomar]* Optionally repeat matching one of the allowed chars excluding the ff Match the mandatory f[diomarf]* Optionally repeat matching one of the allowed chars$ End of string
See a regex101 demo.
Hello everyone and thank you in advance,
I am trying to get a all the words in the following list except for "motiu" and "diomar" using regex and python:
amfora
difamador
difamar
dimorf
dofi
fada
far
farao
farda
fiar
fiord
fira
firar
firma
for
motiu
diomar
The word must not contain a letter outside the list [diomarf], but it must contain an "f"
I don’t know much about regex…I have tried with some, they are getting more complex but I haven’t got the solution yet. Some of the expressions I have tried with are:
> (?:.*f)(?:.*[diomarf])
> (?:.*[diomarf])(?:.*f)
> (?:((?:f)+)(?:[diomarf])*)
> (?:((?:[diomarf])+)(?:f)*)
> (?:((?:[diomarf])*)((?:f)+))
> (?:(((?:f)+)((?:[diomarf])*)))
> (?:((?:f)+((?:[diomarf])*)))
The expression with which I think I got the closest result is:
(?:(((?:f)+)((?:[diomarf])*)))
But it only checks from the first f of the word, for example, for "dimorf" I am only getting the last "f"
^f[diomarf]*$|^[diomarf]*f[diomarf]*$|^[diomarf]*f$
Explanation:
^f[diomarf]*$ : A string either starts with f and then has any number of characters from this list [diomarf] (including 0!)
OR
^[diomarf]*f[diomarf]*$ the string has f somewhere in the middle
OR
^[diomarf]*f$ f at the end
The previous solution I proposed fails when disallowed characters are added to the end of the string (for example diomarfg).
Old solution for reference:
(?=[diomarf]).*f.*
Explanation:
(?=[diomarf]) – use positive lookahead to assert that at any point in the string one of the allowed letters is matched.
.*f.* – make sure that the letter f is somewhere in the string.
You can write the pattern as:
^[diomar]*f[diomarf]*$
Explanation
^Start of string[diomar]*Optionally repeat matching one of the allowed chars excluding theffMatch the mandatoryf[diomarf]*Optionally repeat matching one of the allowed chars$End of string
See a regex101 demo.