Selenium – How to find an element by part of the placeholder value?

Question

Is there any way to find an element by a part of the placeholder value? And ideally, case insensitive.

<input id="id-9" placeholder="some TEXT">

Search by the following function doesn’t work

browser.find_element(by=By.XPATH, value="//input[@placeholder='some te']")

Asked By: Mike

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Source

Answer 1

You can always use contains instead of equals, as following:

browser.find_element(By.XPATH, "//input[contains(@placeholder,'some te')]")

To make it case-insensitive you can use translate function, as following:

browser.find_element(By.XPATH, "//input/@placeholder[contains(translate(., 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz'),'some te')]")

Case-insensitive contains Xpath is taken from this question

Answered By: Prophet

Answer 2

@Prophet’s answer is good, but I wanted to add CSS case too since it may be helpful.
You can use ^= to search for attributes starting with certain keyword and $= for attribute starting with certain keywrd and *= for attribute containing a keyword.

browser.find_element(By.CSS_SELECTOR, 'input[placeholder*="some te"]')

You can make it case-insensitive by adding i before closing the bracket

browser.find_element(By.CSS_SELECTOR, 'input[placeholder*="some te" i]')

Answered By: zaki98

Selenium – How to find an element by part of the placeholder value?

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