python how do i use abs for clockwise?
Question:
im trying to get absolute value between base_pos and postiion but clockwise.
position = [9,12,6]
base_pos = 3
position = sorted(position, key=lambda k: abs(k - base_pos))
print (position)
the code above will give the result of this
[6, 9, 12]
my desired result
[6, 12, 9] #or
[12, 6, 9]
but i want to get [6,12,9] or [12,6,9] because for a clock, 3 is closer to 6 and 9 than 12.
is there any way to accomplish this using abs? if not, is there a good way to do this?
Answers:
Computing distance (0 to 11) in both directions and taking the smaller:
sorted(position, key=lambda k: min((k-base_pos)%12, (base_pos-k)%12))
Your solution is on here
from math import cos, pi
position = [9,11,6,1,2,4,5,7,8,10,12,3]
base_pos = 3
position = sorted(position, key=lambda k: -cos((k%12 - base_pos) * pi / 6))
print (position)
im trying to get absolute value between base_pos and postiion but clockwise.
position = [9,12,6]
base_pos = 3
position = sorted(position, key=lambda k: abs(k - base_pos))
print (position)
the code above will give the result of this
[6, 9, 12]
my desired result
[6, 12, 9] #or
[12, 6, 9]
but i want to get [6,12,9] or [12,6,9] because for a clock, 3 is closer to 6 and 9 than 12.
is there any way to accomplish this using abs? if not, is there a good way to do this?
Computing distance (0 to 11) in both directions and taking the smaller:
sorted(position, key=lambda k: min((k-base_pos)%12, (base_pos-k)%12))
Your solution is on here
from math import cos, pi
position = [9,11,6,1,2,4,5,7,8,10,12,3]
base_pos = 3
position = sorted(position, key=lambda k: -cos((k%12 - base_pos) * pi / 6))
print (position)