How can i achieve like this in python

Question

title = ['james','tom','Kim'] # imagine this is a a file.txt
post_id = [5,6,9] #imagine this is a a file.txt

query = ['james','Kim'] # imagine this is a a file.txt

for i in query:
    print(i)

for name, pid in zip(title, post_id):
    if name == i:
        print(pid)
        break
else:
    print('Not found')

Out Put

james
Kim
9

what im trying to do is i want to make a file.txt listed all post together with their post ID but i have a few item i want to check for a list of specific posts.
How to achieve like this bro?

What I’m Expected Output:

tom = 6
kim = 9

Asked By: LegendCoder

||

Source

Answer 1

You can remove

for i in query:
      print(i)

And remove zip(query, post_id): and use for name in query: to do comparing. By using this your code will loop through every value of query and will compare it with title.

So your final code should be:

title = ['james','tom','Kim'] 
post_id = [5,6,9] 

query = ['james','Kim'] 

for name in query:
   ids = post_id[title.index(name)]
   if name in title:
      print(f"{name} = {ids}")
    
   else:
      print('Not found')

Answered By: Shounak Das

How can i achieve like this in python

Question:

Answers: