Remove first 5 from numbers in a list?
Question:
I have a list with numbers like this :-
s = [5542, 5654, 7545]
The goal is to remove the first 5 from the number such that the resultant list is like this
s = [542, 654, 745]
What’s the best way to achieve the following without using any external libraries?
Answers:
Try this with str.replace(old, new, count) –
[int(str(i).replace('5','',1)) for i in s]
[542, 654, 745]
The str.replace(old, new, count) in this case has 3 parameters, where the count set to 1 will only replace the first instance of 5 it finds in the string.
Then you can convert it back to an integer.
Another solution:
s = [int(str(x)[:str(x).index("5")] + str(x)[str(x).index("5") + 1:]) for x in s]
I have a list with numbers like this :-
s = [5542, 5654, 7545]
The goal is to remove the first 5 from the number such that the resultant list is like this
s = [542, 654, 745]
What’s the best way to achieve the following without using any external libraries?
Try this with str.replace(old, new, count) –
[int(str(i).replace('5','',1)) for i in s]
[542, 654, 745]
The str.replace(old, new, count) in this case has 3 parameters, where the count set to 1 will only replace the first instance of 5 it finds in the string.
Then you can convert it back to an integer.
Another solution:
s = [int(str(x)[:str(x).index("5")] + str(x)[str(x).index("5") + 1:]) for x in s]